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3 years ago

O Mr. Math S. Fun is looking for his missing pair of

Mathematics

1 answer:

Alisiya [41]3 years ago

5 0

Answer:

i think he is missing a pair of red socks

Step-by-step explanation:

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Select the two binomials that are factors of this trinomial below .

PSYCHO15rus [73]

x^2-x-12

factor

what 2 numbers multiply to get -12 and add to get -1?

-4 and 3

(x-4)(x+3)

answer is C and D

6 0

3 years ago

Read 2 more answers

Solve the following equation, and check your solution. Be sure to show all work

fgiga [73]

24 - 3x = -27

therefore -3x = -27-24

-3x = -51
-x= -17
therefore x is 17

7 0

4 years ago

Will appreciate it :)

Sonbull [250]

Answer:

Step-by-step explanation:

In order for lines to be parallel they have to have the same slope. The first 2 equations there are solved for 5y, so let's do that to the last one--solve it for 5y--and put them all in the same order (the order that the first one is in; they will all look identical then). Equation #2 in the same order as in #1: 5y = 3x - 4. Equation #3 then becomes 5y = 3x - 1. Equations #2 and 3 have the same slope.

5 0

3 years ago

Write the slope- intercept form of the equation of the line through (0,3) and (1,1)

PolarNik [594]

Answer:

y = - 2x + 3

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

Calculate m using the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (0, 3) and (x₂, y₂ ) = (1,1)

m = $\frac{1-3}{1-0}$ = - 2

note the line passes through (0, 3) ⇒ c = 3

y = - 2x + 3 ← equation in slope-intercept form

6 0

3 years ago

Explain how to find the vertex of 2x^2+12x+16

Elina [12.6K]

The vertex form:

$y=a(x-h)^2+k\\\\(h,\ k)-vertex$

Use $(a+b)^2=a^2+2ab+b^2\qquad(*)$

$2x^2+12x+16=2(x^2+6x)+16=2(x^2+2(x)(3))+16\\\\=2(\underbrace{x^2+2(x)(3)+3^2}_{(*)}-3^2)+16=2((x+3)^2-9)+16\\\\=2(x+3)^2+(2)(-9)+16=2(x+3)^2-18+16\\\\=\boxed{2(x-(-3))^2-2}\to h=-3,\ k=-2$

<h3>Answer: (-3, -2).</h3>

Other method:

$f(x)=ax^2+bx+c\\\\vertex:(h,\ k)\\\\h=\dfrac{-b}{2a},\ k=f(h)$

We have

$f(x)=2x^2+12x+16\\\\a=2,\ b=12,\ c=16$

Substitute:

$h=\dfrac{-12}{(2)(2)}=\dfrac{-12}{4}=-3\\\\k=f(-3)=2(-3)^2+12(-3)+16=2(9)-36+16=18-36+16=-2$

<h3>Answer: (-3, -2).</h3>

5 0

4 years ago