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Alexeev081 [22]
2 years ago
15

Part B Change the distance of the electron from the center position as it moves up and down. What relationship do you notice bet

ween the distance from the center position and the amplitude of the wave?
Chemistry
1 answer:
pishuonlain [190]2 years ago
7 0

Answer: The movement of the electron changes the amplitude of the wave. The farther the electron moves from the center position, the greater the amplitude.

Explanation:

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An unbalanced chemical equation is shown:
ExtremeBDS [4]

There are 2 Ca, 4 H (2*2) and 4 O (2+2) on the left hand side. So there should be the same number of atoms 2Ca and 4(O+H) on the right hand side.  The reaction is a synthesis (making something new), rather than a decomposition (destroying something).


The answer is Two molecules of Ca(OH)2 should be produced during the synthesis reaction.

4 0
4 years ago
Read 2 more answers
An element 'X after reacting with acids liberates hydrogen gas and candisplace lead and mercury from their salt solutions. The m
adell [148]

The element X is Copper.

Explanation :

Reactive metals from 3d transition series like Cu are very reactive because their standard reduction potential values are low.

Hence, when treated with a acid it tends to liberate hydrogen gas.

Also, because of  its low reduction potential value, it can easily displace lead and tin from their salt solutions.

Learn more :

https://brainly.in/question/6679934

5 0
3 years ago
The following initial rate data are for the reaction of hypochlorite ion with iodide ion in 1M aqueous hydroxide solution: OCI+r
Vinil7 [7]

Answer:

Rate = k [OCl] [I]

Explanation:

OCI+r → or +CI

Experiment [OCI] M I(-M) Rate (M/s)2

1 3.48 x 10-3 5.05 x 10-3 1.34 x 10-3

2 3.48 x 10-3 1.01 x 10-2 2.68 x 10-3

3 6.97 x 10-3 5.05 x 10-3 2.68 x 10-3

4 6.97 x 10-3 1.01 x 10-2 5.36 x 10-3

The table above able shows how the rate of the reaction is affected by changes in concentrations of the reactants.

In experiments 1 and 3, the conc of iodine is constant, however the rate is doubled and so is the conc of OCl. This means that the reaction is in first order with OCl.

In experiments 3 and 4, the conc of OCl is constant, however the rate is doubled and so is the conc of lodine. This means that the reaction is in first order with I.

The rate law is given as;

Rate = k [OCl] [I]

5 0
3 years ago
According to the following reaction, how many moles of Fe(OH)2 can form from 175.0 mL of 0.227 M LiOH solution? Assume that ther
IgorC [24]

Answer:

0.020 moles of Fe(OH)_{2} can be formed

Explanation:

1. First determine the number of moles of LiOH.

Molarity is given by the following expression:

M=\frac{molesofsolute}{Litersofsolution}

Solving for moles of solute:

moles of solute = M * Liters of solution

Converting 175.0mL to L:

175.0mL*\frac{1L}{1000mL}=0.175L

Replacing values:

moles of solute = 0.227M*0.175L

moles of solute = 0.040

Therefore there are 0.040 moles of LiOH

2. Then write the balanced chemical reaction and use the stoichiometry of the reaction to calculate the number of moles of Fe(OH)_{2} produced:

FeCl_{2}(aq)+2LiOH(aq)=Fe(OH)_{2}(s)+2LiCl(aq)

As the problem says that there are excess of FeCl_{2}, the limiting reagent is the LiOH.

0.040molesLiOH*\frac{1molFe(OH)_{2}}{2molesLiOH}=0.020molesFe(OH)_{2} can be formed

3 0
4 years ago
How many liters of bromine are needed to produce 12 miles of aluminum bromide?
VikaD [51]

Answer:

0.929L of Br2

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

2Al + 3Br2 —> 2AlBr3

Next, we shall determine the number of mole of Br2 needed to produce 12 moles of AlBr3. This is illustrated below:

From the balanced equation above,

3 moles of Br2 reacted to produce 2 moles of AlBr3.

Therefore, Xmol of Br2 will produce 12 moles of AlBr3 i.e

Xmol of Br2 = (3 x 12)/2

Xmol of Br2 = 18 moles

Therefore, 18 moles of Br2 reacted to produce 12 moles of AlBr3.

Next, we shall convert 18 moles of Br2 to grams. This is illustrated below:

Number of mole Br2 = 18 moles

Molar mass of Br2 = 2 x 80 = 160g/mol

Mass of Br2 =.?

Mass = mole x molar mass

Mass of Br2 = 18 x 160 = 2880g

Next, we determine the volume of Br2 used in the reaction as follow:

Mass of Br2 = 2880g

Density of Br2 = 3.1g/mL

Volume of Br2 =..?

Density = Mass /volume

Volume = Mass /Density

Volume of Br2 = 2880/3.1

Volume of Br2 = 929mL

Finally, we shall convert 929mL to L.

1000mL = 1L

Therefore, 929mL = 929/1000 = 0.929L

Therefore, 0.929L of Br2 were used in the reaction.

4 0
4 years ago
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