If 9.2 g of calcium react completely with excess aluminum chloride how many grams of aluminum would be produced?

Chemistry

1 answer:

Gekata [30.6K]3 years ago

8 0

Explanation:

3Ca(s) + 2AlCl3(aq) -> 3CaCl2(aq) + 2Al(s)

According to the question, Ca is the limiting reactant.

Therefore, we equate Ca to Aluminium which is the product whose mass we want to find

Molar mass of Ca- 40g/mol

". ". of Al- 27g/mol

3Ca --> 2Al

3×40 --> 2×27

9.2 --> x

x = 9.2×2×27= 496.8÷120=4.14

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