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sergij07 [2.7K]
2 years ago
14

What are the types of lines in engineering drawing?

Engineering
1 answer:
statuscvo [17]2 years ago
8 0
Hi hope this helps you!

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a) Complete the following methods description using the correct tense for the verb in brackets. (This student is using passive v
ExtremeBDS [4]

Answer:

Each of the metal specimens HAS an indentation near the center to ensure that the fracture point would occur in this region. Tension tests WERE CONDUCTED as follows. Two pieces of reflective tape WERE PLACED approximately 1 inch apart in the center of the specimen where the indentation 4 WAS LOCATED. The width and the thickness of the specimen at this location WAS MEASURED using a Vernier caliper. Then the specimen WAS SECURED in the MTS Load Frame. A laser extensometer WAS PLACED into position to measure the deformation of the specimen. The laser extensometer WAS USED to measure the original distance between the pieces of reflective tape. The MTS WAS SET to elongate the specimen one tenth of an inch every minute.

5 0
3 years ago
Investigative personalities prefer to work with:
Andrews [41]

Answer:

Its data

Explanation:

just took the assignment on edge 2021

5 0
3 years ago
A developer has requested permission to build a large retail store at a location adjacent to the intersection of an undivided fo
Sergio [31]

Answer:

676 ft

Explanation:

Minimum sight distance, d_min

d_min = 1.47 * v_max * t_total where v_max is maximum velocity in mi/h, t_total is total time

v_max is given as 50 mi/h

t_total is sum of time for right-turn and adjustment time=8.5+0.7=9.2 seconds

Substituting these figures we obtain d_min=1.47*50*9.2=676.2 ft

For practical purposes, this distance is taken as 676 ft

6 0
3 years ago
A metal crystallizes with a face-centered cubic lattice. The edge of the unit cell is 408 pm. Calculate the number of atoms in t
uysha [10]

Answer:288 pm

Explanation:

Number of atoms(s) for face centered unit cell -

Lattice points: at corners and face centers of unit cell.

For face centered cubic (FCC), z=4.

- whereas

For an FCC lattices √2a =4r =2d

Therefore d = a/√2a = 408pm/√2a= 288pm

I think with this step by step procedure the, the answer was clearly stated.

8 0
3 years ago
1. Which of the following is NOT an example of a lever?
Umnica [9.8K]
A staircase what makes it a lever is another objects used to displace the force better
8 0
4 years ago
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