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DochEvi [55]
2 years ago
8

39 28. If y = (1 - 3x), find the value of dy! dx at x = -1.​

Mathematics
1 answer:
rewona [7]2 years ago
6 0

Answer:

the answer to this question is 52.18

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Help ill mark brainliest
Ann [662]

Answer:

f(4) = -10

g(2) = 30

Step-by-step explanation:

4 0
3 years ago
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(A)+(B)=8 I need help for this question please, and thanks. :) 10 pts!!
Monica [59]
You haven't included enough information for the question, but assuming that a and b are the same then a is 4 and b is 4
7 0
3 years ago
I will give brainliest!! THERE IS NO OTHER INFORMATION GIVEN!! In ⊙O, chord XY is 8 cm long and is 10 cm from O. What is the rad
Zielflug [23.3K]

Answer:

radius ≈ 10.77 cm

Step-by-step explanation:

The segment from the centre O to the chord is a perpendicular bisector.

Thus 2 right triangles are formed with legs 10 cm and 4 cm ( half of XY )

The radius r is the hypotenuse.

Using Pythagoras' identity, then

r² = 4² + 10² = 16 + 100 = 116 ( take the square root of both sides )

r = \sqrt{116} ≈ 10.77 cm ( to 2 dec. places )

4 0
3 years ago
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Select the correct answer from each drop-down menu.
podryga [215]

Answer with explanation:

\text{Average}=\frac{\text{Sum of all the observation}}{\text{Total number of Observation}}

Average Height of tallest Building in San Francisco

                    =\frac{260+237+212+197+184+183+183+175+174+173}{10}\\\\=\frac{1978}{10}\\\\=197.8

Average Height of tallest Building in Los Angeles

                    =\frac{310+262+229+228+224+221+220+219+213+213}{10}\\\\=\frac{2339}{10}\\\\=233.9

→→Difference between Height of tallest Building in Los Angeles and  Height of tallest Building in San Francisco

               =233.9-197.8

               =36.1

⇒The average height of the 10 tallest buildings in Los Angeles is 36.1 more than the average height of the tallest buildings in San Francisco.

⇒Part B

Mean absolute deviation for the 10 tallest buildings in San Francisco

 |260-197.8|=62.2

 |237-197.8|=39.2

 |212-197.8|=14.2

 |197 -197.8|= 0.8

 |184 -197.8|=13.8

 |183-197.8|=14.8

 |183-197.8|= 14.8

 |175-197.8|=22.8

 |174-197.8|=23.8

 |173 -197.8|=24.8

Average of these numbers

     =\frac{62.2+39.2+14.2+0.8+13.8+14.8+14.8+22.8+23.8+24.8}{10}\\\\=\frac{231.2}{10}\\\\=23.12

Mean absolute deviation=23.12

5 0
3 years ago
Need help please.........................
Archy [21]

Answer:

16t^{2} + 2t - 6

Step-by-step explanation:

(12t^{2}  + 5t -y) - (-4t^{2} + 3t -1)

simplify

12t^{2} + 5t -7 +4t^{2} -3t +1

combine like terms

16t^{2} + 2t - 6

8 0
2 years ago
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