Answer:
40·919 m
Explanation:
Initial velocity of the arrow = 46 m/s
Angle at which it is thrown from horizontal = 38°
<h3>At the maximum height, the vertical component of velocity will be 0</h3>
Initial velocity in vertical direction = 46 × sin(38) = 28·32 m/s
From the formula
<h3>v² - u² = 2 × a × s</h3>
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the displacement
Considering the formula in vertical direction and taking upward direction as positive
v = 0
u = 28·32 m/s
a = - g = - 9·8 m/s²
Let s be the maximum height
- 28·32² = - 2 × 9.8 × s
⇒ s = 40·919 m
∴ The arrow will go 40·919 m high
Concave mirror...as it focus the light at a given point..... concave mirror is converging !!!
Answer:
downwards bro now dodododododdodo
We want a sound wave with a wavelength of 0.52 meters or a natural fraction thereof. We'll work in MKS.
w = 0.52/n
That's length. We have speed 344 meters/second so w corresponds to a frequency of
f = 344 / w = n (344/.52)
f = 661.5 n Hertz
I don't really agree with how they're saying it, but all the fundamental talk is probably trying to tell us n=1,
Answer: 661.5 Hertz
Any multiple of that will also produce constructive interference; we can go to about n=30 before we're out of the audio range.
