A sample of argon initially has a volume of 5.0 L and the pressure is 2 atm. If the final temperature is 30° C, the final volume
is 6 L, and the final pressure is 8atm, what was the initial temperature of the argon? Please give answer WITHOUT the unit of KELVIN and round to the tenth position (two places to the right of the decimal). Example: 25.14 not 25.4K
Volume of Argon V1 = 5.0 L Pressure of Argon P1 = 2 atm Final temperature T2 = 30 C = 30 + 273 = 303 K Volume at final temperature V2= 6 L Pressure at final temperature P2 = 8 atm We know that (P1 x V1) / T1 = (P2 x V2) / T2 (2 x 5)/ T1 = (8 x 6)/ 303 => T1 = (10 x 303) / 48 Initial Temperature T1 = 3030 / 48 = 63.12 Initial Temperature = -209. 8 C
