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2 years ago

Use the perfodic table to fill in the table below.

Chemistry

1 answer:

aliina [53]2 years ago

6 0

Answer:

charge

# of Valence

Electrons

# of Energy

Explanation:

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What is the number of proton in this atom

Vilka [71]

Answer:

There are 20 protons

Explanation:

4 0

3 years ago

In the balanced reaction below, what is the mole ratio comparing iron (Fe) and oxygen gas (O2)?

zepelin [54]

The given balanced reaction is,

$4Fe(s) + 3O_{2}(g) --->2Fe_{2}O_{3} (s)$

The stoichiometric coefficients of each element or compound represents the number of moles of that element or compound required for the complete reaction to take place.

The mole ratios of different products and reactants will be:

$\frac{Fe}{O_{2}} = \frac{4 mol Fe}{3 mol O_{2}}$

$\frac{Fe}{Fe_{2}O_{3}} = \frac{4 mol Fe}{2 Fe_{2}O_{3}}$

$\frac{O_{2}}{Fe_{2}O_{3}} =\frac{3 mol O_{2}}{2molFe_{2}O_{3}}$

So the mole ratio comparing iron (Fe) and oxygen gas ( $O_{2}$ ) is

4 : 3

5 0

3 years ago

Read 2 more answers

What is the concentration of a solution that has a volume of 2.5L and contains exactly 2.125 moles of calcium phosphate

Iteru [2.4K]

Answer:

0.85 mol/L.

Explanation:

Molarity is defined as the no. of moles of solute dissolved in a liter of the solution.

M = (no. of moles of solute)/(Volume of the solution (L))

no. of moles of calcium phosphate = 2.125 mol.

Volume of the solution = 2.5 L.

∴ M of calcium phosphate = (2.125 mol)/(2.5 L) = 0.85 mol/L.

7 0

3 years ago

A compound has a molar mass of 100 g/mol and the percent composition (by mass) of 65.45% C, 5.45% H, and 29.09% 0. Determine the

coldgirl [10]

Answer:

B) C3H3O and C6H6O2

Explanation:

Given data:

Molar mass of compound = 100 g/mol

Percentage of hydrogen = 5.45%

Percentage of carbon = 65.45%

Percentage of oxygen = 29.09%

Empirical formula = ?

Molecular formula = ?

Solution:

Number of gram atoms of H = 5.45 / 1.01 = 5.4

Number of gram atoms of O = 29.09/ 16 = 1.8

Number of gram atoms of C = 65.45 / 12 = 5.5

Atomic ratio:

C : H : O

5.5/1.8 : 5.4/1.8 : 1.8/1.8

3 : 3 : 1

C : H : O = 3 : 3 : 1

Empirical formula is C₃H₃O.

Molecular formula:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

Empirical formula mass = 12×3 + 1.01 ×3 + 16×1 = 55.03

n = 100 / 5503

n = 2

Molecular formula = n (empirical formula)

Molecular formula = 2 (C₃H₃O)

Molecular formula = C₆H₆O₂

3 0

3 years ago

How many significant gigures are in each mesasurments 303,000mm

Triss [41]

3 Sig FIgs in 303,000 mm
Any nonzero is a sig fig.
Any zero between two non zeros is a sig fig.

5 0

3 years ago