Explain the following observations
1 answer:
You might be interested in
The question is incomplete, complete question is :
The frequency factors for these two reactions are very close to each other in value. Assuming that they are the same, compute the ratio of the reaction rate constants for these two reactions at 25°C.
Activation energy of the reaction 1 , = 14.0 kJ/mol
Activation energy of the reaction 2, = 11.9 kJ/mol
Answer:
0.4284 is the ratio of the rate constants.
Explanation:
According to the Arrhenius equation,
The expression used with catalyst and without catalyst is,
where,
= rate constant reaction -1
= rate constant reaction -2
Activation energy of the reaction 1 , = 14.0 kJ/mol = 14,000 J
Activation energy of the reaction 2, = 11.9 kJ/mol = 11,900 J
R = gas constant = 8.314 J/ mol K
T = temperature =
Now put all the given values in this formula, we get
0.4284 is the ratio of the rate constants.
Answer:
PBr3 - Molecule , Polar
N2H2 - Molecule , (Polar in E- form and Non- polar in Z form)
C2H2 - Molecule , Non- Polar
N2 - Molecule , Polar
NCl3 - Molecule , Polar
SiF4 - Molecule , Non- Polar
NH3 - Molecule , Polar
F - Not- Molecule (atom)
H2 - Molecule and Non- Polar
Explanation:
Molecule : these are group of two or more atoms joined by strong force of attraction.
H2 is non- polar because it is homoatomic molecule.(made up of same element)
N2 is non- polar because it is homoatomic molecule.
Answer:
capacity factor = 0.952
Availability factor = 0.958
Explanation:
1) capacity factor
capacity factor = actual power output / maximum power output
= (actual power output)/(efficiency * rated power output)
= 0.952
2) Availability factor
Availability factor = Actual operation time period/ total time period
= 23/24 = 0.958