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3 years ago

Two bodies of mass m₁ & m₂ are moving with the same velocity 'v' K.E. will be greater for??

Physics

1 answer:

boyakko [2]3 years ago

8 0

Answer:

the one with a higher mass

Explanation:

The body with more mass will have the greater kinetic energy of the two.

Kinetic energy is the energy due to the motion of body. It is mathematically expressed as:

K.E = $\frac{1}{2}$ m v²

m is the mass

v is the velocity

Since the velocity of the two bodies are the same, and mass is directly proportional to kinetic energy, the body with more mass will have a higher kinetic energy.

So between mass m1 and mass m2, the one with a greater mass will have a higher kinetic energy

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When an object moves in uniform circular motion, the direction of its acceleration is?

Harrizon [31]

Clock wise idk i think you should double check my answer

7 0

3 years ago

A box of paper is labeled 24lb paper. This means that 500 sheets (counted number) of paper size 17in x 22in weighs 24 pounds (Th

Tresset [83]

Answer:

The mass of a single paper is approximately 0.047 lb/paper which in SI Units is approximately 21.77 g/paper

Explanation:

The given information on the size and the weight of paper are;

The mass of a box of 500 sheets of paper = 24 lb

The number of sheets in the paper = 500 sheets

The dimensions of the paper = 17 in. × 22 in., which is equivalent to 43.18 cm × 55.88 cm

The mass of a single paper = The mass of the box of paper/(The number of sheets of paper present in the box)

The mass of a single paper = 24 lb/500 = 0.047 lb/paper

Given that 1 lb = 453.6 g, we have;

0.047 lb/paper = 0.047 lb/paper×453.6 g/(lb) = 21.77 g/paper

The mass of a single paper = 0.047 lb/paper = 21.77 g/paper.

6 0

3 years ago

A force of 100 N acts upward. Resolve this force into 2 components; one that acts 30º north of west and one that acts 60º north

GrogVix [38]

To resolve these forces we have to make use of the sines and cosines.

To resolve this force in 30 degree north of west, the answer will be

100*sin(30)

The answer will be 50N

Now to resolve the force acting 60 degree north of east

100* cos(60)

The answer will be 50N.

This also adds to the total force acting that is 50+50=100N. This is the way forces are resolved according to their specified angles.

5 0

3 years ago

You are at the controls of a particle accelerator, sending a beam of 3.60 x10^7 m/s protons (mass m) at a gas target of an unkno

matrenka [14]

Answer:

a) mass of unknown nucleus = 0.04245 mp, where mp is the proton mass

b) Speed of the unknown nucleus = (7.067 x 10^7) m/s

Explanation:

Considering the initial conditions, the observed collisions are ellastic, i.e, the total kinetic energy are conserved. The proton's mass will refer as $m_{p}$ .

(a)

Total kinetic energy conservation

$\frac{1}{2}m_{p}v_{p_0}^{2}+\frac{1}{2}m_{u}v_{u_o}^{2}=\frac{1}{2}m_{p}v_{p_f}^{2}+\frac{1}{2}m_{u}v_{u_f}^{2}$

where $v_{u_o}$ represents the initial velocity of the unknown element, $m_{u}$ the mass of the unknown element, and $v_{u_f}$ the final velocity of the unknown element

Linear momentum conservation

$m_{p}v_{p_0}+m_{u}v_{u_o}=m_{p}v_{p_f}+m_{u}v_{u_f}$

Using the initial speed of the target nucleus (unknown) is negligible, i.e, its speed is zero. Thereby, using the relation of linear momentum conservation given above, it is possible to find an expression of the final speed of the unknown nucleus in terms of its mass, which can be inserted in the relation of the kinetic energy conservation to obtain the value of the mass of the unknown elements, as follows;

$m_{u}v_{u_f}=m_{p}v_{p_0}-m_{p}v_{p_f}\\\\v_{u_f}=\frac{m_{p}(v_{p_0}-v_{p_f})}{m_{u}}$

Substituting this expression in the relation of total kinetic energy conservation,

$m_{p}(v^{2}_{p_0}-v^{2}_{p_f})={m_{u}}v^{2}_{u}_{f}$

Then,

$m_{p}(v^{2}_{p_0}-v^{2}_{p_f})={m_{u}}\frac{m^{2}_{p}(v_{p_0}-v_{p_f})^{2}}{m^{2}_{u}}\\\\m_{u}= \frac{m_{p}(v_{p_0}-v_{p_f})^{2}}{(v^{2}_{p_0}-v^{2}_{p_f})}$

Replacing the given data

$m_{u}= \frac{m_{p}(3.6x10^{7}-3.3x10^{7})^{2}}{((3.6x10^{7})^{2}-(3.3x10^{7})^{2})}$

Then,

$m_{u}=0.04245m_{p}$

(b) Using the relation of the final speed from linear momentum conservation and the above result, the speed of the unknown nucleus is calculated

$v_{u_f}=\frac{m_{p}(v_{p_0}-v_{p_f})}{m_{u}}\\\\v_{u_f}=\frac{m_{p}(3.6x10^{7}-3.3x10^{7})}{0.04245m_{p}}\\\\v_{u_f}=7.067x10^{7} m/s$

5 0

3 years ago

1. horizontal row in the periodic table____ 2. vertical column in the periodic table____ 3. A repetition of properties occurs wh

Anna11 [10]

Answer:

1. Periods

2. Groups of families

3. the statement is true about Periodic law

4. metals

5.transition metals

6.atomic radius

7. cations

8. electrons

9. electronegativity of the atom

10. ionization energy

Explanation:

1. horizontal row in the periodic table____are called Periods

2. vertical column in the periodic table____ are called Groups of families

3. A repetition of properties occurs when elements are arranged in order of increasing atomic number.____ True about Periodic Law (most elements that fall within the same families has similar properties)

4. type of element that is a good conductor of heat and electric current____ are metals that are found in group 1 and 2 of the periodic table Boron, tin, silver, Zinc, Alluminium, Germanium, Pollonium, antimony, e.t.c

5. type of element characterized by the presence of electrons in the dorbital____are called transition metals

6. one-half the distance between the nuclei of two atoms when the atoms are joined____ are called atomic radius

7. type of ion formed by Group 2A elements____are Cations

8. subatomic particles that are transferred to form positive and negative ions____ are called electrons

9. ability of an atom to attract electrons when the atom is in a compound____ is called electronegativity of the atom

10. energy required to remove an electron from an atom is called ionization energy

4 0

3 years ago