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Naddik [55]
2 years ago
13

Two bodies of mass m₁ & m₂ are moving with the same velocity 'v' K.E. will be greater for??

Physics
1 answer:
boyakko [2]2 years ago
8 0

Answer:

the one with a higher mass

Explanation:

The body with more mass will have the greater kinetic energy of the two.

Kinetic energy is the energy due to the motion of body. It is mathematically expressed as:

           K.E  = \frac{1}{2}  m v²

m is the mass

v is the velocity

 Since the velocity of the two bodies are the same, and mass is directly proportional to kinetic energy, the body with more mass will have a higher kinetic energy.

 So between mass m1 and mass m2, the one with a greater mass will have a higher kinetic energy

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Two uniform solid cylinders, each rotating about its central (longitudinal) axis, have the same mass of 2.88 kg and rotate with
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Answer:

(a) K_{small}=4839.3J

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Explanation:

Given data

The angular velocity of two cylinders ω=257 rad/s

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The radius of small cylinder r₁=0.319 m

The radius of larger cylinder r₂=0.605 m

For Part (a)

The rotational kinetic energy of the cylinder is given by:

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Where I is rotational of inertia of solid cylinder about its central axis.

So

K=\frac{1}{2}Iw^2\\ K=\frac{1}{2}(1/2mr^2)w^2

Substitute the given values

So

K_{small}=\frac{1}{4}(2.88kg)(0.319)^2(257rad/s)^2 \\K_{small}=4839.3J

For Part (b)

K=\frac{1}{2}Iw^2\\ K=\frac{1}{2}(1/2mr_{2}^2)w^2

Substitute the given values

K_{larger}=\frac{1}{4}mr_{2}^2w^2\\ K_{larger}=\frac{1}{4}(2.88kg)(0.605m)^2(257rad/s)^2\\ K_{larger}=17406.4J

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