on a given inclined we know that net force is given by
here we know that
so here we have
so here acceleration depends directly on angle of inclination
now we also know that if height of the inclined is H and its length is L
then we can write
so the acceleration is given as
so acceleration also depends directly on height of the inclined plane
1 horsepower is equivalent to 0.7457
Kilo Newton. I am hoping that this answer has satisfied your query and it will
be able to help you in your endeavor, and if you would like, feel free to ask
another question.
Answer:
Read this entry from a blog about service dogs.
Lexie, an eight-month-old black Labrador retriever, is sleeping quietly at my feet. I can’t help but think that her soft, velvety ears and alert brown eyes would make her the perfect “doggie model” for pet magazines and pet store ads. However, Lexie will soon have a much more important job to do. In a few months, she will become the loyal companion and service dog for a young man who has been blind since birth. She will help him board public transportation, such as buses, subways, and trains, and she will help him safely cross busy intersections. Lexie will even help the young man avoid obstacles, such as high curbs and low overhangs. Like all dogs in our organization, Lexie has undergone months of specialized training to help a visually impaired person lead an active and independent life.
What is the secondary purpose of this blog?
to inform readers about seeing-eye dogs
to entertain readers with details about Lexie
to persuade readers to train service dogs
to convince readers to adopt Labrador retrievers
Explanation:
The answer would be conduction. hope that helped
Answer:
v = - 1,715 m / s
, x = 0.0156 m
Explanation:
This is an oscillatory movement exercise, which is described by the expression
x = A cos (wt + Ф)
we can assume that the block is released from its maximum elongation, so the phase constant (Ф) is zero
As we are told that the stone does not affect the movement of the spring mass system, the amplitude and angular velocity do not change, in the upward movement the stone is attached to the mass, but in the downward movement the mass has an acceleration greater than g leave the stone behind, let's look for time, for this we use the definition of speed and acceleration
v = dx / dt
v = - A w sin wt
a = - Aw² cos wt
a = -g
-g = - Aw² cos wt
wt = cos⁻¹ (g / Aw²)
t = 1 / w cos⁻¹ (g / Aw²)
angular velocity and frequency are related
w = 2π f
w = 2π 4
w = 8π rad / s
remember that the angles are in radians
t = 1 / 8π cos⁻¹ (9.8 / (0.07 64π²))
t = 0.039789 1.3473
t = 0.0536 s
let's find the speed for this time
v = - A w sin wt
v = - 0.07 8π sin (8π 0.0536)
v = - 1,715 m / s
the distance is
x = A cos wt
x = 0.07 cos (8π 0.0536)
x = 0.0156 m
