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Natasha_Volkova [10]
3 years ago
13

20 points for an answer Explain how the distance of a planet from the sun affects the motion of the planet? Justify your respons

e in two or more complete sentences.
Physics
2 answers:
Nataliya [291]3 years ago
4 0
The sun’s huge mass gives it a strong gravitational pull. Because of this gravitational pull, planets that are closer to the sun tend to have different motion than planets that are further away from the sun, because the gravity becomes stronger the closer you get. I hope this helped!
jekas [21]3 years ago
3 0

The sun’s huge mass gives it a strong gravitational pull. Because of this gravitational pull, planets that are closer to the sun tend to have different motion than planets that are further away from the sun, because the gravity becomes stronger the closer you get. I hope this helped!

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Illustrated here are three different<br> of carbon. They vary by the number of
Basile [38]

D) isotopes; neutrons

Explanation:

The diagram illustrates the three different isotopes of carbon. They vary by the number of neutrons.

Isotopy is the existence of two or more atoms of the same element having the same atomic number but different mass numbers due to the differences in the number of neutrons in their various nuclei.

  • Isotopes of elements have the same electronic configuration
  • They share the same chemical properties
  • They differ in masses due the number of neutrons they contain.

Learn more:

Isotopes brainly.com/question/1915462

#learnwithBrainly

5 0
3 years ago
A wooden block with mass 1.05 kg is placed against a compressed spring at the bottom of a slope inclined at an angle of 35.0 deg
Svet_ta [14]

Answer:

Explanation:

energy stored in spring initially

= kinetic + potential energy of block + energy dissipated by friction

= 1/2 mv² + mgh + μ mgcosθ x  d

m is mass , v is velocity at top position , h is vertical height , μ is coefficient of friction ,θ is angle of inclination of plane

= m (1/2 v² + gh + μ gcosθ x  d )

= 1.05 ( .5 x 5.1² + 9.8 x 4.9 sin35 + .55 x 9.8 cos35 x 4.9 )

= 1.05 ( 13.005 + 27.543 + 21.635)

= 65.3 J .

4 0
3 years ago
Calculate the heat energy required to increase the temperature of 3 kg of water by 20ºC. The specific heat capacity of water is
Marina86 [1]

Answer:

Heat energy required = 252000J or 252KJ.

Explanation:

<u>Given the following data;</u>

Mass = 3kg

Temperature = 20ºC

Specific heat capacity of water = 4200 J/kg°C

To find the heat energy required;

Heat capacity is given by the formula;

Q = mct

Where;

  • Q represents the heat capacity or quantity of heat.
  • m represents the mass of an object.
  • c represents the specific heat capacity of water.
  • t represents the temperature.

Substituting into the equation, we have;

Q = 3*4200*20

Q = 252000 Joules or 252 Kilojoules.

6 0
3 years ago
An ore sample weighs 17.50 N in air. When the sample is suspended by a light cord and totally immersed in water, the tension in
valkas [14]

Answer:

Volume of the sample: approximately \rm 0.6422 \; L = 6.422 \times 10^{-4} \; m^{3}.

Average density of the sample: approximately \rm 2.77\; g \cdot cm^{3} = 2.778 \times 10^{3}\; kg \cdot m^{3}.

Assumption:

  • \rm g = 9.81\; N \cdot kg^{-1}.
  • \rho(\text{water}) = \rm  1.000\times 10^{3}\; kg \cdot m^{-3}.
  • Volume of the cord is negligible.

Explanation:

<h3>Total volume of the sample</h3>

The size of the buoyant force is equal to \rm 17.50 - 11.20 = 6.30\; N.

That's also equal to the weight (weight, m \cdot g) of water that the object displaces. To find the mass of water displaced from its weight, divide weight with g.

\displaystyle m = \frac{m\cdot g}{g} = \rm \frac{6.30\; N}{9.81\; N \cdot kg^{-1}} \approx 0.642\; kg.

Assume that the density of water is \rho(\text{water}) = \rm  1.000\times 10^{3}\; kg \cdot m^{-3}. To the volume of water displaced from its mass, divide mass with density \rho(\text{water}).

\displaystyle V(\text{water displaced}) = \frac{m}{\rho} = \rm \frac{0.642\; kg}{1.000\times 10^{3}\; kg \cdot m^{-3}} \approx 6.42201 \times 10^{-4}\; m^{3}.

Assume that the volume of the cord is negligible. Since the sample is fully-immersed in water, its volume should be the same as the volume of water it displaces.

V(\text{sample}) = V(\text{water displaced}) \approx \rm 6.422\times 10^{-4}\; m^{3}.

<h3>Average Density of the sample</h3>

Average density is equal to mass over volume.

To find the mass of the sample from its weight, divide with g.

\displaystyle m = \frac{m \cdot g}{g} = \rm \frac{17.50\; N}{9.81\; N \cdot kg^{-1}} \approx 1.78389 \; kg.

The volume of the sample is found in the previous part.

Divide mass with volume to find the average density.

\displaystyle \rho(\text{sample, average}) = \frac{m}{V} = \rm \frac{1.78389\; kg}{6.42201 \times 10^{-4}\; m^{3}} \approx 2.778\; kg \cdot m^{-3}.

3 0
3 years ago
4. Three methods that people use are:
Mila [183]
The answers to question 4 d
6 0
2 years ago
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