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Allisa [31]
3 years ago
10

Can you help me pls

Physics
1 answer:
Kruka [31]3 years ago
7 0

Answer:

The student can conclude that as the bulb is not lighting up so the object can be insulator

Explanation:

PLEASE MARK ME BRAINLIEST IF MY ANSWER IS CORRECT PLEASE

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F = 130 revs/min = 130/60 revs/s = 13/6 revs/s
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wf = 0 rads/s = wi + at
a = -wi/t = -13π/3 × 1/31 = -13π/93 rads/s²
wf² - wi² = 2a∅
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∅ = 1209π/18 rads
n = ∅/2π = (1209π/18)/(2π) = 1209/36 ≈ 33.5833 revolutions.
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