Question

Determine the moment of inertia of a 14.8 kg sphere of radius 0.752 m when the axis of rotation is through its center.

Answer 1

Answer:

$I=3.348Kgm^2$

Explanation:

From the question we are told that:

Mass $m=14.8kg$

Radius$r=0.752m$

Generally the equation for inertia is mathematically given by

$I=\frac{2}{5}mR^2$

$I=\frac{2}{5}14.8*(0.752)^2$

$I=3.348Kgm^2$