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Alborosie
2 years ago
14

Determine the moment of inertia of a 14.8 kg sphere of radius 0.752 m when the axis of rotation is through its center.

Physics
1 answer:
vfiekz [6]2 years ago
6 0

Answer:

I=3.348Kgm^2

Explanation:

From the question we are told that:

Mass m=14.8kg

Radiusr=0.752m

Generally the equation for inertia is mathematically given by

I=\frac{2}{5}mR^2

I=\frac{2}{5}14.8*(0.752)^2

I=3.348Kgm^2

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