3 years ago

Determine the moment of inertia of a 14.8 kg sphere of radius 0.752 m when the axis of rotation is through its center.

Physics

1 answer:

vfiekz [6]3 years ago

6 0

Answer:

$I=3.348Kgm^2$

Explanation:

From the question we are told that:

Mass $m=14.8kg$

Radius $r=0.752m$

Generally the equation for inertia is mathematically given by

$I=\frac{2}{5}mR^2$

$I=\frac{2}{5}14.8*(0.752)^2$

$I=3.348Kgm^2$

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