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Sedaia [141]
3 years ago
9

A 72.0-kg object hits the ground at a velocity of 79.0 m/s. Neglecting air resistance, which relationship allows you to calculat

e the object’s potential energy before the fall? A. PE = mgh B. (PE)beginning = (KE)end C. Mechanical Energy = PE + KE D. KE = 1/2 mv2
Physics
1 answer:
kondaur [170]3 years ago
8 0
<h3>Answer:</h3>

B. (PE)beginning = (KE)end

<h3>Explanation:</h3>

<u>We are given;</u>

  • Mass of an object is 72.0 kg
  • Velocity of the body before it hits the ground is 79.0 m/s

We are required to determine the relationship between the potential energy and kinetic energy before the fall.

  • When an object is at the highest point, it has maximum potential energy and minimum kinetic energy.
  • This is because potential energy is directly proportional to the height of an object above the earth's surface.
  • On the other hand, when an object attains the highest speed it has maximum kinetic energy and minimum kinetic energy.

In this case;

  • The velocity of the object when hitting the ground is maximum and thus the object will have maxim,um kinetic energy.
  • As the object falls towards the ground the potential energy is being converted to kinetic energy.
  • Therefore, the potential energy at the beginning will be equal to the kinetic energy at the end when the object is on the ground.
  • We can therefore, conclude that, (PE)beginning = (KE)end
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