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Sedaia [141]
3 years ago
9

A 72.0-kg object hits the ground at a velocity of 79.0 m/s. Neglecting air resistance, which relationship allows you to calculat

e the object’s potential energy before the fall? A. PE = mgh B. (PE)beginning = (KE)end C. Mechanical Energy = PE + KE D. KE = 1/2 mv2
Physics
1 answer:
kondaur [170]3 years ago
8 0
<h3>Answer:</h3>

B. (PE)beginning = (KE)end

<h3>Explanation:</h3>

<u>We are given;</u>

  • Mass of an object is 72.0 kg
  • Velocity of the body before it hits the ground is 79.0 m/s

We are required to determine the relationship between the potential energy and kinetic energy before the fall.

  • When an object is at the highest point, it has maximum potential energy and minimum kinetic energy.
  • This is because potential energy is directly proportional to the height of an object above the earth's surface.
  • On the other hand, when an object attains the highest speed it has maximum kinetic energy and minimum kinetic energy.

In this case;

  • The velocity of the object when hitting the ground is maximum and thus the object will have maxim,um kinetic energy.
  • As the object falls towards the ground the potential energy is being converted to kinetic energy.
  • Therefore, the potential energy at the beginning will be equal to the kinetic energy at the end when the object is on the ground.
  • We can therefore, conclude that, (PE)beginning = (KE)end
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Answer:

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Explanation:

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First of all, we need to get the value of g.

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At the highest point in the trajectory, just before of changing direction, the stone comes momentarily to a stop.

At this point, applying the definition of acceleration, we can write:

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We have the total time since the stone was thrown upwards, not the one used for the upward trajectory.

It can be showed, using the expression for the displacement (which is the same in both directions) that the time used for going up, it's the same used to go down, so the time that we need to put in (1). is just the half of the total time.

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Before solving for mp, however, we need to get the value of the radius of the planet.

Assuming that it's a perfect sphere, we can get this value from the value of the circumference at the planet's equator:

rp = 2*π*rp / 2*π ⇒ rp = 1.0*10⁵ km / 2*π = 15,915 km.

With this value for  rp, we can solve (2) for mp, as follows:

mp= g*rp² / G = 3.33 m/s² * (15,915 km)² / 6,67*10⁻¹¹ N.m²/kg²

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ok??

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