Answer:
Explanation:
412 ATP's will be generated from the complete metabolic oxidation of tripalmitin (tripalmitoylglycerol)
130 ATP from the oxidation of palmitate
22 ATP from the oxidation of glycerol
Altogether 130 + 22 = 412 ATP will be produced.
Here in case of tripalmitin (tripalmitoylglycerol), we have 51 carbons.
When 51 carbons can produce 412 ATPs
Then 1 carbon will produce how many ATPs = 412 ATPs/ 51 carbon= 8.1 ATPs.
This shows that ATP yield per carbon often oxidized will be 8.1 ATPs
Now we will see the ATP yield in the case of glucose.
Glucose is made up of 6 carbon and complete oxidation of glucose will produce 38 ATPs
When 6 carbons can yield 38 ATPs
Then 1 carbon can yield how many ATPs= 38 ATPs/ 6 carbons= 6.33 ATPs.
So, ATP yield per carbon in case of glucose will be 6.33 ATPs
Elements are substances that are made up of the same atoms which are capable of taking part in a chemical reaction.
There are different types of elements which are represented by symbols gotten from the first letter or the first and any other letter in the name of the element.
Examples of elements include:
When two or more of these elements combine together through a chemical bond, it leads to the formation of compounds.
Example of a compound includes:
- NaCl: The element sodium combine, through electrochemical bonding, with another element chlorine to form the compound sodium chloride.
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The question is cut off in the picture
Answer: Bacteria from the fecal transplant can fill up the space in the gut, limiting the food and space for invading harmful bacteria.fecal transplants may be best answer to antibiotic-resistant bacteria: Non-pharmaceutical treatment combats recurring Clostridium Difficile infections
Explanation:
Answer is: (2) Chemical energy is converted to electrical energy.
An electrochemical cell (voltaic or galvanic cell) is generating electrical energy from chemical reactions.
In galvanic cell, specie (for example zinc and zinc cations) from one half-cell, lose electrons (oxidation) and species from the other half-cell (for example copper and copper cations) gain electrons (reduction).
Oxidation on the zinc anode: Zn(s) → Zn²⁺(aq) + 2e⁻.
Reduction on the copper cathode: Cu²⁺(aq) + 2e⁻ → Cu(s).
