The center of a circle whose equation is x^2 +y^2 – 12x – 2y +12 = 0 is (6,1)
<h3>Equation of a circle</h3>
The standard equation of a circle is expressed as:
x^2 + y^2 + 2gx + 2fy + c = 0
where:
(-g, -f) is the centre of the circle
Given the equations
x^2 +y^2 – 12x – 2y +12 = 0
Compare
2gx = -12x
g = -6
Simiarly
-2y = 2fy
f = -1
Centre = (6, 1)
Hence the center of a circle whose equation is x^2 +y^2 – 12x – 2y +12 = 0 is (6,1)
Learn more on equation of a circle here: brainly.com/question/1506955
His father is 47 years old 23+24=47
I don’t see the table necessary in order to solve this question
Answer:
C. 
Step-by-step explanation:
To find slope using coordinates, use the formula above.
Now, using the 
formula, plug in 
as 
(slope) and either coordinate as the 
and 
values. It looks like this:
To solve for 
, continue to use PEMDAS.
Now use and to solve for your equation:
The answer is C.
