Ada got a new puppy for Christmas. She went to the pet store to buy the

Line segment Y A is an altitude of ΔXYZ. What is the length of Line segment Y A?

worty [1.4K]

Answer:

A on edge

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

What is the perimeter of a parallelogram, if it's area is 36 cm^2 and the distances between the point of intersection of the dia

IgorC [24]

Answer:

The perimeter of a parallelogram is 30cm.

Step-by-step explanation:

From the question , the given area of a parallelogram is 36 cm².

But the area of a parallelogram can be calculated using below formula

Area = base * height

From the question the distances that exist between the point of intersection of the diagonals and the sides are 2cm and 3cm respectively

There is the same distance between point of intersection of the diagonals and the opposite sides then,

The base of the side with 4cm can be calculated as

ha= 2+ 2= 4cm

But area can be calculated as A= base × height

36= b1 × h1

36=b1 × 4

b1= 9cm

The base of the other side can be calculated with 6cm height

h2= 3+3=6cm

A= b2× h2

36= b2 ×h2

36= b2× 6

b2= 6cm

Then the perimeter of the parallelogram can be calculated as

P= 2(b1 + b2)

= 2(6+9)

= 30cm

Hence,the perimeter of the parallelogram is 30cm

4 0

3 years ago

Which sets of side lengths could form a triangle? Choose all that apply.

svlad2 [7]

What are the answer choices

4 0

3 years ago

(3-4i)(6i+7)-(2-3i)

Sergeu [11.5K]

Answer:

43-7i

Step-by-step explanation:

We are given the expression:

$\displaystyle \large{(3 - 4i)(6i + 7) - (2 - 3i)}$

First, expand 3-4i in 6i+7. To expand binomial with binomial, first we expand 3 in 6i+7 then expand -4i in 6i+7.

$\displaystyle \large{[(3 \cdot 6i) + (3 \cdot 7) + ( - 4i \cdot 6i) + ( - 4i \cdot 7)]- (2 - 3i)} \\ \displaystyle \large{[18i + 21 - 24 {i}^{2} - 28i]- (2 - 3i)}$

Now combine like terms.

$\displaystyle \large{[ - 10i+ 21 - 24 {i}^{2} ]- (2 - 3i)}$

Imaginary Unit

$\displaystyle \large{i = \sqrt{ - 1} } \\ \displaystyle \large{ {i}^{2} = - 1 }$

Therefore:-

$\displaystyle \large{[ - 10i+ 21 - 24 ( - 1) ]- (2 - 3i)} \\ \displaystyle \large{[ - 10i+ 21 + 24]- (2 - 3i)} \\ \displaystyle \large{[ - 10i+ 45]- (2 - 3i)}$