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2 years ago

If a pendulum takes 2 sec to swing in each direction, find the period and the frequency of the swing

1 answer:

8 0

The period ( measured in s) is the amount of time is takes for the pendulum to make a single cycle, i.e. how long it takes to swing in both direction. The frequency (measured in Hz) is the inverse of the period, the number of cycles it completes in one second.

So long as you know one you can find the other by diving 1 by it. Period = 1 / frequency, and frequency = 1 / period

If the pendulum takes 2s in each direction, then it has a period of 4s. So the frequency = 1 / 4s = 0.25Hz

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3 years ago

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2 years ago

Consider two Carnot heat engines operating in series. The first engine receives heat from the reservoir at 1400 K and rejects th

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The temperature T= 648.07k

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T1=input temperature of the first heat engine =1400k

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but carnot efficiency of heat engine = $1 - \frac{Tl}{Th} \\$

where Th =temperature at which the heat enters the engine

Tl is the temperature of the environment

since both engines have the same thermal capacities <em> $n_{th}$ </em> therefore $n_{th} =n_{th1} =n_{th2}\\n_{th }=1-\frac{T1}{T}=1-\frac{T}{T3}\\ \\= 1-\frac{1400}{T}=1-\frac{T}{300}\\$

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$\frac{-1400}{T}+\frac{T}{300}=0\\$

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- $420000+ T^{2} =0\\T^2 =420000\\\sqrt{T2}=\sqrt{420000} \\T=648.07k$

The temperature T= 648.07k

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2 years ago