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icang [17]
3 years ago
15

If a pendulum takes 2 sec to swing in each direction, find the period and the frequency of the swing

Engineering
1 answer:
DaniilM [7]3 years ago
8 0
The period ( measured in s) is the amount of time is takes for the pendulum to make a single cycle, i.e. how long it takes to swing in both direction. The frequency (measured in Hz) is the inverse of the period, the number of cycles it completes in one second.

So long as you know one you can find the other by diving 1 by it. Period = 1 / frequency, and frequency = 1 / period

If the pendulum takes 2s in each direction, then it has a period of 4s. So the frequency = 1 / 4s = 0.25Hz
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Which of the following Identifies the challenges faced by scientists experimenting with using artificial photosynthesis as
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3 years ago
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3 years ago
An aluminum oxide component must not fail when a tensile stress of 12.5 MPa is applied. Determine the maximum allowable surface
aivan3 [116]

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1.44 mm

Explanation:

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Substituting the given values

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4 0
3 years ago
A strip ofmetal is originally 1.2m long. Itis stretched in three steps: first to a length of 1.6m, then to 2.2 m, and finally to
andreyandreev [35.5K]

Answer:

strains for the respective cases are

0.287

0.318

0.127

and for the entire process 0.733

Explanation:

The formula for the true strain is given as:

\epsilon =\ln \frac{l}{l_{o}}

Where

\epsilon = True strain

l= length of the member after deformation

l_{o} = original length of the member

<u>Now for the first case we have</u>

l= 1.6m

l_{o} = 1.2m

thus,

\epsilon =\ln \frac{1.6}{1.2}

\epsilon =0.287

<u>similarly for the second case we have</u>

l= 2.2m

l_{o} = 1.6m   (as the length is changing from 1.6m in this case)

thus,

\epsilon =\ln \frac{2.2}{1.6}

\epsilon =0.318

<u>Now for the third case</u>

l= 2.5m

l_{o} = 2.2m

thus,

\epsilon =\ln \frac{2.5}{2.2}

\epsilon =0.127

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l_{o} = 1.2m

thus,

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\epsilon =0.733

6 0
3 years ago
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