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arlik [135]
2 years ago
12

How do the data support your claim above?

Chemistry
2 answers:
olya-2409 [2.1K]2 years ago
3 0

Answer:

i need more information give me more pictures

Explanation:

lol

quester [9]2 years ago
3 0
We need pictures of your data to answer this question
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Need help with the question
Sloan [31]

Answer:

for a i think it is choice 2

for b i think it is the first choice

Explanation:

3 0
3 years ago
Energy can be changed from potential to kinetic.<br> A.True<br> B.False
vampirchik [111]

Answer:

An object has potential energy (stored energy) when it is not in motion. Once a force has been applied or it begins to move the potential energy changes to kinetic energy (energy of motion).

Therefore, true. (Also would u mind giving brainliest, you don't have to hehe)

6 0
3 years ago
What is the volume of 3.40 mol of gas at 33.3C and 22.2atm of pressure
Luda [366]
The volume of 3.40 mol of gas at 33.3 C and 22.2 atm of pressure is 3.85 liter of gas. This problem can be solved by using the PV=nRT or V= nRT/V equation which is the relation between the molar volume, the temperature, and the pressure of gas. In this formula, P is the pressure, R is the universal gas constant ( 0.0821 atm L/mol K), n is the molecule amount, V is the molecular volume, and T is the temperature. The temperature used in this formula must be in Kelvin, therefore we have to convert the Celcius temperature into Kelvin temperature (33.3 C = 306.45 K).
<span>The calculation for the problem above: 3.4*0.0821*306.45/22.2 = 3.85 liter of gas.</span>
5 0
3 years ago
The sulfur dioxide (so2) stack-gas concentration from fossil-fuel combustion is 12 ppmv. determine the stack-gas so2 concentrati
sergejj [24]

The concentration of SO_{2} in the stack gas = 12 ppmv

That means 12 L of  SO_{2} is present per 10^{6} L gas

The given temperature is 273 K (0 C) and pressure is 1 atm. At these conditions, 1 mol of gas would occupy,

PV = nRT

(1 atm) (V) = (1 mol)(0.08206\frac{L.atm}{mol.K}) (273 K)

V = 22.4 L

1 mol SO_{2} occupies 22.4 L

Moles of SO_{2} = 12 L *\frac{1 mol}{22.4 L} = 0.5357 mol SO_{2}

Mass of  SO_{2} =0.5357 mol *\frac{64.06 g}{1 mol}  = 34.32 g SO_{2}  *\frac{10^{6} microgram}{1 g} =3.432 *10^{7}μg

Converting 10^{6} L to m^{3}:

10^{6} L *\frac{1 m^{3}}{1000 L} = 10^{3}   m^{3}

Calculating the concentration in μg/m^{3}:

\frac{3.432 * 10^{7} microgram}{10^{3} L}    = 3.432 * 10^{4}  microgram/m^{3}

3 0
3 years ago
Help ill give brainliest need help with number 8
kotegsom [21]

Answer:

the sun goes away and takes heat with it

Explanation:

5 0
3 years ago
Read 2 more answers
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