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valentina_108 [34]
3 years ago
9

The sulfur dioxide (so2) stack-gas concentration from fossil-fuel combustion is 12 ppmv. determine the stack-gas so2 concentrati

on in units of µg/m3. assume 0 °c and 1 atm pressure. express answer to nearest unit.
Chemistry
1 answer:
sergejj [24]3 years ago
3 0

The concentration of SO_{2} in the stack gas = 12 ppmv

That means 12 L of  SO_{2} is present per 10^{6} L gas

The given temperature is 273 K (0 C) and pressure is 1 atm. At these conditions, 1 mol of gas would occupy,

PV = nRT

(1 atm) (V) = (1 mol)(0.08206\frac{L.atm}{mol.K}) (273 K)

V = 22.4 L

1 mol SO_{2} occupies 22.4 L

Moles of SO_{2} = 12 L *\frac{1 mol}{22.4 L} = 0.5357 mol SO_{2}

Mass of  SO_{2} =0.5357 mol *\frac{64.06 g}{1 mol}  = 34.32 g SO_{2}  *\frac{10^{6} microgram}{1 g} =3.432 *10^{7}μg

Converting 10^{6} L to m^{3}:

10^{6} L *\frac{1 m^{3}}{1000 L} = 10^{3}   m^{3}

Calculating the concentration in μg/m^{3}:

\frac{3.432 * 10^{7} microgram}{10^{3} L}    = 3.432 * 10^{4}  microgram/m^{3}

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