Answer:
(1,0)
Step-by-step explanation:
Absolute value is represented by using these bars → ║.
║= number of units from 0.
This equation says that whatever number is in the absolute value bars , x , is greater than y.
<span>
The vertices of a polygon are given as follows: P(-2,4), Q(4,2), R(4,0); S(-12,0); k = 0.5 Find the coordinates of the vertex P' of the image after a dilation having the given scale factor. Type your answers as a coordinate pair in this format: (x,y)</span>
Answer: Exact Form: x = 7/2
Decimal Form: x = 3.5
Mixed Number Form: x = 3 1/2
How to: <u>
Solve for x by simplifying both sides of the equation, then isolating the variable.</u>
Have a great day and stay safe !
The general equation of a circle is
(x-a) ^ 2 + (y-b) ^ 2 = r ^ 2
for this case the values of a and b are
a = 2
b = 0
The radius of the circle is
r ^ 2 = 14
r = (14) ^ (1/2) = 3.74
I solved this using a scientific calculator and in radians mode since the given x's is between 0 to 2π. After substitution, the correct pairs
are:
cos(x)tan(x) – ½ = 0
→ π/6 and 5π/6
cos(π/6)tan(π/6) – ½ = 0
cos(5π/6)tan(5π/6) – ½ = 0
sec(x)cot(x) + 2 =
0 → 7π/6 and 11π/6
sec(7π/6)cot(7π/6) + 2 = 0
sec(11π/6)cot(11π/6) + 2 = 0
sin(x)cot(x) +
1/sqrt2 = 0 → 3π/4 and 5π/4
sin(3π/4)cot(3π/4) + 1/sqrt2 = 0
sin(5π/4)cot(5π/4) + 1/sqrt2 = 0
csc(x)tan(x) – 2 = 0 → π/3 and 5π/3
csc(π/3)tan(π/3) – 2 = 0
csc(5π/3)tan(5π/3) – 2 = 0
