Question

Water was added to 175 mL of a KOH solution until the volume was 250 mL and the molarity was 0.315 M. What was the molarity of the initial concentrated solution?

Answer 1

Answer:  The molarity of the initial concentrated solution is 0.450 M

Explanation:

According to the dilution law,

$M_1V_1=M_2V_2$

where,

$M_1$ = Molarity of concentrated KOH solution = ?

$V_1$ = volume of  concentrated KOH solution = 175 ml

$C_2$ = concentration of diluted KOH solution= 0.315 M

$V_2$ = volume of diluted KOH solution= 250 ml

Putting in the values, we get:

$M_1\times 175=0.315\times 250$

$M_1=0.450M$

Thus the molarity of the initial concentrated solution is 0.450 M