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Free_Kalibri [48]
3 years ago
8

What is the net force when forces applied are 300 N to the right and 100 N to the right

Physics
1 answer:
labwork [276]3 years ago
8 0

Answer:

400 Newtons to the right.

Explanation:

You have 300 Newtons that are being applied to the right and you also 100 Newtons to the right. When calculating net force with the forces that go the same direction, you add them. 300 plus 100 is 400. Therefore, it is 400 Newtons or N to the right. Hope this helps!

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A scientist compares two samples of white powder. One powder was present at the beginning of an experiment. The other powder was
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Density of powder 1 = 0.5 g / 45 cm^3 = 1/90 g/cm^3
Density of powder 2 = 1.3 g / 65 cm^3 = 1/50 g/cm^3

Therefore the densities of the two powders are different, hence chemical reaction has occurred.

(note: none of the other choices make sense.  In fact, a different density does not necessarily indicate a chemical change, see paragraph below).

Density of powders are not definitive unless they are each of the same size and texture.  For example, granular sugar, rock sugar, and icing sugar all have different densities.  I would conclude that this experiment does not lend to a reliable answer.
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3 years ago
An object has a kinetic energy of 14 j and a mass of 17 kg how fast is the object moving
Brilliant_brown [7]
  • KE=14J
  • Mass=m=17kg
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\\ \sf\Rrightarrow kE=\dfrac{1}{2}mv^2

\\ \sf\Rrightarrow 14=\dfrac{1}{2}17v^2

\\ \sf\Rrightarrow 17v^2=28

\\ \sf\Rrightarrow v^2=28/17

\\ \sf\Rrightarrow v^2=1.64

\\ \sf\Rrightarrow v\approx 0.13m/s

5 0
3 years ago
For the graph above, what is the independent variable? What is the dependant variable?
posledela
Time/sec. the x-axis is always the independent variable.
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3 years ago
The MRI (Magnetic Resonance Imaging) body scanners used in hospitals operate at a frequency of 400 MHz (M = 106 ). Calculate the
horrorfan [7]

Answer:

Energy, E=2.65\times 10^{-25}\ J

Explanation:

It is given that,

The MRI (Magnetic Resonance Imaging) body scanners used in hospitals operate at a frequency of 400 MHz,

\nu=400\ MHz=400\times 10^6\ Hz=4\times 10^8\ Hz

We need to find the energy for a photon having this frequency. The energy of a photon is given by :

E=h\nu

E=6.63\times 10^{-34}\ J-s\times 4\times 10^8\ Hz

E=2.65\times 10^{-25}\ J

So, the energy of the photon is 2.65\times 10^{-25}\ J. Hence, this is the required solution.

6 0
3 years ago
n the figure, a uniform ladder 12 meters long rests against a vertical frictionless wall. The ladder weighs 400 N and makes an a
Leto [7]

Since the ladder is standing, we know that the coefficient of friction is at least something. This [gotta be at least this] friction coefficient can be calculated. As the man begins to climb the ladder, the friction can even be less than the free-standing friction coefficient. However, as the man climbs the ladder, more and more friction is required. Since he eventually slips, we know that friction is less than what's required at the top of the ladder.

 

The only "answer" to this problem is putting lower and upper bounds on the coefficient. For the lower one, find how much friction the ladder needs to stand by itself. For the most that friction could be, find what friction is when the man reaches the top of the ladder.

Ff = uN1

Fx = 0 = Ff + N2

Fy = 0 = N1 – 400 – 864

N1 = 1264 N

Torque balance

T = 0 = N2(12)sin(60) – 400(6)cos(60) – 864(7.8)cos(60)

N2 = 439 N

Ff = 439= u N1

U = 440 / 1264 = 0.3481

3 0
3 years ago
Read 2 more answers
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