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lutik1710 [3]
4 years ago
6

Does a steep plane prove more mechanical advantage than a gradual plane

Physics
1 answer:
Alexxx [7]4 years ago
7 0

Answer:

No

Explanation:

It just doesn't. At all.

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An object is released from height of 17m. <br> The object will hit the ground approximately in
zzz [600]

\text{Given that,}\\\\\text{Height, h = 17 m}\\\\\\\text{We know that,}\\\\h = v_0t + \dfrac 12  gt^2\\\\\implies h = \dfrac 12 gt^2\\\\\implies t^2 = \dfrac{2h}g\\\\\implies t =\sqrt{\dfrac{2h}g} = \sqrt{\dfrac{2(17)}{9.81}} = 1.87 ~ \text{sec}

5 0
2 years ago
If an organism can not reproduce,is it still considered living?why?
zlopas [31]
The ability to reproduce is essential for a species, but not for an individual. There are some people that can't reproduce, but they're still alive!
6 0
3 years ago
what do we call a solar power plant that uses mirrors to focus the light of the sun on a central point
Mars2501 [29]

Answer:

Concentrating solar power (CSP) plants use mirrors to concentrate the sun's energy to drive traditional steam turbines or engines that create electricity.

Explanation:

4 0
3 years ago
A box is at rest on a ramp at an incline of 22°. The normal force on the box is 538 N.
fomenos

Answer: 580 N

Refer to attached figure.

The angle of inclination is 22 degrees

weight (gravitational force) acts downwards.

Normal force is a contact force which acts perpendicular to the point of contact.

The horizontal component (mg cos 22 ) balances the normal force and the vertical component balances the frictional force.

Gravitational force on an object = mg

The normal force N= mg cos 22

\Rightarrow mg =\frac{N}{cos22}=\frac{538 N}{0.927}=580 N





8 0
3 years ago
Read 2 more answers
What is the heat capacity of an object at 25.5∘C that absorbs 45 kJ of heat and is heated to 28.2∘C?
sergey [27]

Answer:

16.6 kJ/°C

Explanation:

given,

Amount of heat absorbed = 45 kJ

initial temperature, T₁ = 25.5°C

final temperature, T₂ = 28.2°C

change in temperature = T₂ - T₁

                                       = 28.2 - 25.5  = 2.7° C

Heat\ capacity = \dfrac{Heat\ absorbed}{\Delta T}

Heat\ capacity = \dfrac{45\ kJ}{2.7}

Heat\ capacity = 16.6\ kJ/^0C

Heat capacity of the object is equal to 16.6 kJ/°C

4 0
4 years ago
Read 2 more answers
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