All categories

3 years ago

Please help!!!! 70 points, i really need this! D:

Physics

2 answers:

jolli1 [7]3 years ago

7 0

1. Frequency 2. measure from trough to trough

Nadusha1986 [10]3 years ago

6 0

Number 1 is frequency

Number 2 is C

Number 3 is D

<h2>I tried my best and i think there right!!</h2>

You might be interested in

A ball of mass of 0.5kg is dropped from a height of 2m.

erastovalidia [21]

Answer:

6.3m/s

Explanation:

Given parameters:

Mass of the ball = 0.5kg

Height = 2m

Unknown:

Velocity when the ball hits the ground = ?

Solution:

Since the potential energy is transformed into kinetic energy;

P.E = K.E

mgh = $\frac{1}{2}$ m v²

cancelling m;

gh = $\frac{1}{2}$ v²

v² = 2gh

v = √2gh

Insert the parameters and solve;

v = √2gh = √ 2 x 9.8 x 2 = 6.3m/s

3 0

3 years ago

A long wire carrying I=1.1A of constant current oriented North-to-South (and the current is running northwards) is placed horizo

Tema [17]

Answer:

The absolute value of the angular deviation is 39.3°.

Explanation:

Given that,

Current = 1.1 A

Distance = 0.9 cm

Magnetic field = 20μT

We need to calculate the magnetic field due to wire

Using formula of magnetic field

$B=\dfrac{\mu_{0}I}{2\pi d}$

Put the value into the formula

$B=\dfrac{4\pi\times10^{-7}\times1.1}{2\pi\times0.9\times10^{-2}}$

$B=24.4\times10^{-6}\ T$

$B=24.4\ \mu T$

We need to calculate the absolute value of the angular deviation

Using formula of direction

$\theta=\tan^{-1}(\dfrac{B_{E}}{B_{w}})$

$\theta=\tan^{-1}(\dfrac{20 \mu}{24.4 \mu})$

$\theta=39.3^{\circ}$

Hence, The absolute value of the angular deviation is 39.3°.

5 0

3 years ago

One electron collides elastically with a second electron initially at rest. After the collision, the radii of their trajectories

morpeh [17]

Answer:

63.750KeV

Explanation:

We are given that

Initial velocity of second electron, $u_2=0$

Radius, $r_1=0$

$r_2=2.3 cm=\frac{2.3}{100}=0.023 m$

1 m=100 cm

Magnetic field,B=0.0370 T

We have to determine the energy of the incident electron.

Mass of electron, $m=9.1\times 10^{-31} kg$

Charge on an electron, $q=-1.6\times 10^{-19} C$

Velocity, $v=\frac{Bqr}{m}$

Using the formula

Speed of electron, $v_1=\frac{Bqr_1}{m}=\frac{0.0370\times 1.6\times 10^{-19}\times 0}{9.1\times 10^{-31}}=0$

Speed of second electron, $v_2=\frac{0.0370\times 1.6\times 10^{-19}\times 0.023}{9.1\times 10^{-31}}$

$v_2=1.5\times 10^8 m/s$

Kinetic energy of incident electron= $\frac{1}{2}mv^2_1+\frac{1}{2}mv^2_2$

Kinetic energy of incident electron= $0+\frac{1}{2}(9.1\times 10^{-31})(1.5\times 10^8)^2=1.02\times 10^{-14} J$

Kinetic energy of incident electron= $\frac{1.02\times 10^{-14}}{1.6\times 10^{-19}}=63750eV=\frac{63750}{1000}=63.750KeV$

1KeV=1000eV

3 0

3 years ago

a sprinter's whose mass is 70 kg accelerstes from rest to 11 m/s in 6 seconds what is the acceleration what force did this requi

mr Goodwill [35]

666666666666666666666666666666666666666666666666

6 0

3 years ago

One example of a physical change is

ycow [4]

Answer:

Mixing a milkshake

Explanation:

Becuse it’s physics becuse your using muscle and moving it and changing it by force.

7 0

3 years ago