It would be volume.
Volume is not an intensive property because it <em>does</em> change as the amount of substance increases or decreases. The rest of the properties are constant no matter the amount of substance.
Answer: - 986.6 kj/mol
Explanation:
1) Equation given:
CaO(s) + H₂O (l) → Ca (OH)₂ (s) δh⁰ = −65.2 kj/mol
2) Standard enthalpies of formation given:
CaO, δhf⁰ = −635.6 kj/mol
H₂O, δhf⁰ = −285.8 kj/mol
3) Calculate the standard enthalpy of formation of Ca(OH)₂.
δh⁰ = ∑δh⁰f of products - ∑ δh⁰f of reactants
Using the mole coefficients of the balanced chemical equation:
δh⁰ = δh⁰f Ca(OH)₂ - δh⁰f CaO - δh⁰f H₂O
⇒ δh⁰f Ca(OH)₂ = δh⁰ + δh⁰f CaO + δh⁰f H₂O
⇒ δh⁰f Ca(OH)₂ = - 65.2 kj/mol − 635.6 kj/mol) − 285.8 kj/mol) = - 986.6 kj/mol.
Answer:
Kush would have been able to fight better and probably would have never been invaded by Egypt, and they could have beaten the Assyrians when they tried to takeover Egypt. And the 25th dynasty would have continued.
Explanation:
that is my explanation and answer^
Answer:
0.174 M
Explanation:
The same can be solve by using Nernst's equation
The Nernst's equation is:
![Ecell=E^{0}_{cell}-\frac{0.0592}{n}log\frac{[anodic]}{[cathodic]}](https://tex.z-dn.net/?f=Ecell%3DE%5E%7B0%7D_%7Bcell%7D-%5Cfrac%7B0.0592%7D%7Bn%7Dlog%5Cfrac%7B%5Banodic%5D%7D%7B%5Bcathodic%5D%7D)
For silver cell
n= 1
As both the compartments have silver nitrate solution,t the standard emf of cell will be zero.
Given
Ecell = 0.045
[Anodic compartment]= 1 M
Putting values
Taking antilog and solving
[AgNO3]=0.174 M
