Explanation:
Method of prepration of sodium thiosulphate - definition
In the laboratory, this salt can be prepared by heating an aqueous solution of sodium sulphite with sulphur or by boiling aqueous NaOH and sulfur according to this equation:
Answer:
676mmHg
Explanation:
Using the formula;
P1/T1 = P2/T2
Where;
P1 = initial pressure (mmHg)
P2 = final pressure (mmHg)
T1 = initial temperature (K)
T2 = final temperature (K)
According to the information provided in this question;
P1 = 725.0mmHg
P2 = ?
T1 = 20°C = 20 + 273 = 293K
T2 = 0°C = 0 + 273 = 273K
Using P1/T1 = P2/T2
725/293 = P2/273
Cross multiply
725 × 273 = 293 × P2
197925 = 293P2
P2 = 197925 ÷ 293
P2 = 676mmHg.
The resulting pressure is 676mmHg
Answer:
kinetic energy than the potential energy it carries
Explanation:
Answer:
The best answer is "E"
NaCl leaves the ascending limb of the loop of Henle through active transport.
Explanation:
The loop of Henle is a U-shaped portion of the tubule that conducts urine within each nephron. It's principal function is the recovery of water and sodium chloride from the urine.
The ascending limb is impermeable to water. NaCl is pumped from the tubule into the interstitium in the ascending limb by active transport. This active transport enables the kidney to establish an osmotic gradient which enables the permeability of water and urea thereby allowing the kidneys to concentrate the urine.
6+2=8 quarts of a new solution
0.45*6 - quarts antifreeze in <span>a solution that is 45% antifreeze
0.19*2 - </span>quarts antifreeze in a solution that is 19% antifreeze
x- concentration of a new solution
8x - quarts antifreeze in a new solution
0.45*6 + 0.19*2 = 8x
3.08=8x
x= 0.385 =38.5 %
