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Stels [109]
3 years ago
5

1. Calculate the mass (in grams) of 3.8 moles of the following:

Chemistry
1 answer:
muminat3 years ago
4 0

Explanation:

Given;

  Number of moles of the elements = 3.8moles

Molar mass of Gold  = 196.966g/mol

Molar mass of Magnesium  = 24.3g/mol

Molar mass of Tin  = 118.710g/mol

Molar mass of Bromine  = 79.904g/mol

   Mass  = number of moles x molar mass

Mass of Gold = 3.8 x 196.966  = 748.5g

 Mass of Magnesium  = 3.8 x 24.3  = 92.3g

Mass of Tin  = 3.8 x 118.710  = 451.1g

Mass of Bromine  = 3.8 x 79.904  = 303.6g

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2 years ago
True or false: The force exerted onto an object must be perpendicular to the displacement if work is to be considered done.
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Explanation:

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3 years ago
ASAP WILL GIVE BRAINLIEST!!
Nataly_w [17]

Answer:

The answer to your question is a) N₂     b) 3.04 g of NH₃

Explanation:

Data

mass of H₂ = 2.5 g

mass of N₂ = 2.5 g

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molar mass of N₂ = 28.02 g

molar mass of NH₃ = 17.04 g

Balanced chemical reaction

                3H₂  +  1 N₂   ⇒   2NH₃

A)

Calculate the theoretical yield 3H₂ / N₂ = 3(2.02) / 28.02 = 0.22

Calculate the experimental yield H₂/N₂ = 2.5/2.5 = 1

Conclusion

The limiting reactant is N₂ (nitrogen) because the experimental proportion was higher than the theoretical proportion.

B)

             28.02 g of N₂ -------------------- (2 x 17.04) g of NH₃

               2.5 g of N₂    --------------------   x

                            x = (2.5 x 2 x 17.04) / 28.02

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6 0
3 years ago
2. Determine the molarity of the NaOH solution in each trial. a. Trial 1 Molarity: b. Trial 2 Molarity: 3. Calculate the average
butalik [34]

Answer:

This question is incomplete

Explanation:

This question is incomplete but...

1) You can calculate the molarity of the NaOH for each trial by following the steps below.

The formula for Molarity (M) is

M = number of moles (n) ÷ volume (V)

where the unit of volume must be in Litres or dm³

The unit of molarity is mol/dm³ or mol/L or molar conc (M)

The final answer must have the unit of molarity

If the number of moles is not provided, look out for the mass of NaOH used and then calculate your number of moles (n) as

n = mass of NaOH used ÷ molar mass of NaOH

Where the atomic mass of sodium (Na) is 23, oxygen (O) is 16 and hydrogen (H) is 1. Hence, molar mass for NaOH is 23 + 16 + 1 = 40 g/mol

n = mass of NaOH used ÷ 40

2) Average Molarity will be (Trial 1 Molarity +Trial 2 Molarity) ÷ 2

Answer must be in mol/dm³ or mol/L or M

3) Label the volumentric flask containing the NaOH solution with the answer gotten from (2) above

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