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photoshop1234 [79]
2 years ago
11

How much does the Earth weigh? Have an AWESOME day -NaomiTheGenuis

Physics
2 answers:
lapo4ka [179]2 years ago
6 0

\bold{Heya!}

<h2><u>How much does the Earth weigh ?</u></h2>

<u />

Such a good question, Sir or Ma'am !

Answer ヾ(•ω•`)o

\sf{5.972 \: x \: 10^2^4 ^k^g}

Hopefully This Helps ! ~

#LearnWithBrainly

\underline{Answer :}

<em>Jaceysan ~</em>

<em />

<em />

babymother [125]2 years ago
3 0

Answer:

The Earth weighs about:
13,170,000,000,000,000,000,000,000 pounds

or

5.97 billion trillion metric tons



Explanation:

Have a great rest of your day
#TheWizzer

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According to the nebular theory, what early event eventually led to the formation of our solar system?​
qaws [65]

Answer:Solar system formed about 4.6 billion year ago, when gravity pulled together low-density cloud of interstellar gas and dust (called a nebula)(movie). The Orion Nebula, an interstellar cloud in which star systems and possibly planets are forming. Initially the cloud was about several light years across.

Explanation:

4 0
2 years ago
How much water
nevsk [136]

Answer:

The mass is  m  =  3.75 \  kg

Explanation:

From the question we are told that

     The initial temperature is  T_1 =  15^oC

      The final  temperature is  T_2 =  100 ^o C  \ (boiling point )

Generally the maximum heat produced by  1  Liter   of  natural gas is  9000 \ cal

 So the amount of heat produced by 100 L is  

              E = 9000 * 100

=>           E = 9000 00 \  cal

Generally given that the efficiency is  \eta =  0.35

Then actual heat received by the water is

         H  =  0.35 *  E

=> H  =  0.35 *   9000 00

=> H  =  315000 \  cal

Converting to kcal  

=> H  =  315000 \  cal = \frac{315000}{1000} =  315 \ kcal

Generally the specific heat of water is  

       c_w  =  1 kcal/ kg \cdot ^oC

Generally the heat received by the water is mathematically represented as

       H  =  m *  c_w  *  (T_2 - T_1)

=>     315  =  m *  1   *  ( 100  - 15 )

=>     m  =  3.75 \  kg

     

6 0
3 years ago
Water is entering the prism at a rate of A m^3/hr. The prism is empty at time 0. Express the depth d of the water in meters in t
zavuch27 [327]

This question is incomplete, the complete question is;

The picture shows a triangular prism. The end of prism are equilateral triangles with x meters. the other dimension of the prism is L meters

a) Find the volume V in terms of x and L

b) Water is entering the prism at a rate of A m³/hr. The prism is empty at time 0. Express the depth d of the water in meters in terms of A, the length of time t the water has been entering the trough, and the length L of the prism.  

Answer:

a) the volume V in terms of x and L is  ((√3/4)x²L) m³

b) required expression is (2/(3)^(1/u))√(At/L)

Explanation:

Given that;

form the question and image below;

triangular prism ends are equilateral triangle

side length = x meter

Dimension of the prism = L meter

Area of the equilateral triangle = √3/4 (side)² = √3/4 (x)² meter

Volume of the triangular prism = Area × height

= √3/4 (x)² × L

V = ((√3/4)x²L) m³

Therefore, the volume V in terms of x and L is  ((√3/4)x²L) m³

b)

Rate of water entering = A m³/hr

Depth of water tank = d meter

Time = t

Length of prism = L

now Rate of water entering is A m³/hr

dv/d = A                             [  V = ((√3/4)x²L) m³ ]

and

dv/dt = √3/4 [2x dx/dt ] L                   { L is constant }

so

A = √3/4 [2x dx/dt ] L  

∫A dt = √3/2 [ Lx dx ]                   { Integrate both sides}

At = √3/2 × Lx × x²/2

x² = uAt / √3L                              { we find square root of both sides}

x = √( uAt / √3L )

x = (2/(3)^(1/u))√(At/L)

Therefore; required expression is (2/(3)^(1/u))√(At/L)

8 0
2 years ago
Caleb rides his motorcycle with a constant speed of 72km/h. How far can he Travel in 3 hours 40 minutes
lina2011 [118]
264 km

72 x 3 hr = 216 km
72/60 (min in an hr) =  1.2(km per min) x 40 = 48 km
216 + 48 = 264

5 0
3 years ago
Helppp pls yes or no question
svp [43]

Answer:

yes, should be

Explanation:

This is a hard yes or no question becuase the amplitudes are the same height but in different beating orders.

7 0
2 years ago
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