The power developed is 500 W ( to the nearest Watt)
Power(P) is the rate at which work is done. Work done (W) is the product of the force applied on the object and the displacement (s) made by the point of application of the force.
![P = \frac{W}{t}](https://tex.z-dn.net/?f=%20P%20%3D%20%5Cfrac%7BW%7D%7Bt%7D%20%20)
![W= F*s](https://tex.z-dn.net/?f=%20W%3D%20F%2As%20)
Therefore,
![P=\frac{F*s}{t}](https://tex.z-dn.net/?f=%20P%3D%5Cfrac%7BF%2As%7D%7Bt%7D%20%20)
Substitute the given values of force , displacement and time
![F = 124 N,s = 32.0 m,t = 8.0 s](https://tex.z-dn.net/?f=%20F%20%3D%20124%20N%2Cs%20%3D%2032.0%20m%2Ct%20%3D%208.0%20s%20)
![P =\frac{W*s}{t} =\frac{124N*22.0s}{8.0s} =496 W](https://tex.z-dn.net/?f=%20P%20%3D%5Cfrac%7BW%2As%7D%7Bt%7D%20%3D%5Cfrac%7B124N%2A22.0s%7D%7B8.0s%7D%20%3D496%20W%20)
Thus the Power can be rounded off to the nearest value of 500 W
Work done = force * distance
work done = 200 * 20
work done = 4000J
Answer:
The charge on the dust particle is ![q_d = 6.94 *10^{-13} \ C](https://tex.z-dn.net/?f=q_d%20%20%3D%206.94%20%2A10%5E%7B-13%7D%20%5C%20%20C)
Explanation:
From the question we are told that
The length is ![l = 2.0 \ m](https://tex.z-dn.net/?f=l%20%3D%202.0%20%5C%20m)
The width is ![w = 4.0 \ m](https://tex.z-dn.net/?f=w%20%3D%204.0%20%5C%20m)
The charge is ![q = -10\mu C= -10*10^{-6} \ C](https://tex.z-dn.net/?f=q%20%3D%20%20-10%5Cmu%20C%3D%20-10%2A10%5E%7B-6%7D%20%5C%20C)
The mass suspended in mid-air is ![m_a = 5.0 \mu g = 5.0 *10^{-6} \ g = 5.0 *10^{-9} \ kg](https://tex.z-dn.net/?f=m_a%20%3D%20%205.0%20%5Cmu%20g%20%3D%20%205.0%20%2A10%5E%7B-6%7D%20%5C%20g%20%3D%20%205.0%20%2A10%5E%7B-9%7D%20%5C%20%20kg)
Generally the electric field on the carpet is mathematically represented as
![E = \frac{q}{ 2 * A * \epsilon _o}](https://tex.z-dn.net/?f=E%20%3D%20%20%5Cfrac%7Bq%7D%7B%202%20%2A%20%20A%20%20%2A%20%20%5Cepsilon%20_o%7D)
Where
is the permittivity of free space with value ![\epsilon_o = 8.85*10^{-12} \ \ m^{-3} \cdot kg^{-1}\cdot s^4 \cdot A^2](https://tex.z-dn.net/?f=%5Cepsilon_o%20%3D%208.85%2A10%5E%7B-12%7D%20%20%5C%20%5C%20%20m%5E%7B-3%7D%20%5Ccdot%20kg%5E%7B-1%7D%5Ccdot%20%20s%5E4%20%5Ccdot%20A%5E2)
substituting values
![E = \frac{-10*10^{-6}}{ 2 * (2 * 4 ) * 8.85*10^{-12}}](https://tex.z-dn.net/?f=E%20%3D%20%20%5Cfrac%7B-10%2A10%5E%7B-6%7D%7D%7B%202%20%2A%20%20%282%20%2A%204%20%29%20%20%2A%20%208.85%2A10%5E%7B-12%7D%7D)
![E = -70621.5 \ N/C](https://tex.z-dn.net/?f=E%20%3D%20-70621.5%20%5C%20%20N%2FC)
Generally the electric force keeping the dust particle on the air equal to the force of gravity acting on the particles
![F__{E}} = F__{G}}](https://tex.z-dn.net/?f=F__%7BE%7D%7D%20%3D%20%20F__%7BG%7D%7D)
=> ![q_d * E = m * g](https://tex.z-dn.net/?f=q_d%20%2A%20%20E%20%20%3D%20%20m%20%2A%20g)
=> ![q_d = \frac{m * g}{E}](https://tex.z-dn.net/?f=q_d%20%20%3D%20%20%5Cfrac%7Bm%20%2A%20g%7D%7BE%7D)
=> ![q_d = \frac{5.0 *10^{-9} * 9.8}{70621.5}](https://tex.z-dn.net/?f=q_d%20%20%3D%20%20%5Cfrac%7B5.0%20%2A10%5E%7B-9%7D%20%2A%209.8%7D%7B70621.5%7D)
=> ![q_d = 6.94 *10^{-13} \ C](https://tex.z-dn.net/?f=q_d%20%20%3D%206.94%20%2A10%5E%7B-13%7D%20%5C%20%20C)
Answer:
Fuel oil is mixed with a proper portion of compressed air
Explanation:
A gas turbine has three main part, which are
- combustion chamber
- air compressor
- power turbine
The combustion chamber is responsible for mixing fuel with a proper portion of compressed air.
The air compressor supplies air in sufficient quantity to satisfy the requirements of the combustion chamber
The power turbine produces the power to drive the air compressor.