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krek1111 [17]
3 years ago
14

A 81 kg block is released at a 3.8 m height. the track is frictionless. the block travels down the track, hits a massless spring

constant k=1888.calculate the average force
Physics
1 answer:
Alenkinab [10]3 years ago
8 0
Since the track is friction less, block’s kinetic energy at the bottom of the track is equal to its potential energy at the top of the track. 
PE = 81 * 9.8 * 3.8 = 3016.44 J
 Work = 1/2 * 1888 * d^2  
PE = Kinetic energy at the base.
 1/2 * 1888 * d^2 = 3016.44
 d = 1.78 approx 1.8
 F = Ke = 1888 * 1.8 = 3398.4N
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r_2 = 1.586r_1

Therefore the factor of average radio of her blood vessels increased is 1.589 the initial factor after the increase.

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