Ask question

Ask question

All categories

2 years ago

9

If it takes you 10 seconds to move a chair 5 meters across the floor, using a force of 2 Newtons, how much power did you put out

?
20 joules per second

100 joules per second

O 1 joules per second

4 joules per second

1 answer:

Maru [420]2 years ago

5 0

Answer:

power=work done÷time taken

2×5=10

10÷10=1

ans 1J per second

You might be interested in

A student performs Young’s double-slit experiment with slits that are separated by 0.160 mm. She observes the interference patte

Bogdan [553]

Answer:

Wavelenght is 4.53x10^-7m

Explanation:

Detailed explanation and calculation is shown in the image below

5 0

3 years ago

As stars age and become larger they become ________ and ________

sleet_krkn [62]

They become old and explode.

5 0

3 years ago

Explain why you cannot use mass or volume alone to identify substances.

Alex17521 [72]

Objects can have the same mass (but different <span>compositions). Only mass or volume cannot tell you if the object is solid or vo</span>lumes) or same volume (but different masses)

4 0

3 years ago

A trick shot archer shoots an arrow with a velocity of 30.0 m/s at an angle of 20.0 degrees with respect to the horizontal. An a

svlad2 [7]

Answer:

$u'=10.259\ m.s^{-1}$ is the initial velocity of tossing the apple.

the apple should be tossed after $\Delta t=0.0173\ s$

Explanation:

Given:

velocity of arrow in projectile, $v=30\ m.s^{-1}$

angle of projectile from the horizontal, $\theta=20^{\circ}$

distance of the point of tossing up of an apple, $d=30\ m$

<u>Now the horizontal component of velocity:</u>

$v_x=v\ cos\ \theta$

$v_x=30\times cos\ 20^{\circ}$

$v_x=28.191\ m.s^{-1}$

<u>The vertical component of the velocity:</u>

$v_y=v.sin\ \theta$

$v_y=30\times sin\ 20^{\circ}$

$v_y=10.261\ m.s^{-1}$

<u>Time taken by the projectile to travel the distance of 30 m:</u>

$t=\frac{d}{v_x}$

$t=\frac{30}{28.191}$

$t=1.0642\ s$

<u>Vertical position of the projectile at this time:</u>

$h=v_y.t-\frac{1}{2}g.t^2$

$h=10.261\times 1.0642-\frac{1}{2} \times 9.8\times 1.0642^2$

$h=5.3701\ m$

<u>Now this height should be the maximum height of the tossed apple where its velocity becomes zero.</u>

$v'^2=u'^2-2g.h$

$0^2=u'^2-2\times 9.8\times 5.3701$

$u'=10.259\ m.s^{-1}$ is the initial velocity of tossing the apple.

<u>Time taken to reach this height:</u>

$v'=u'-g.t'$

$0=10.259-9.8\times t'$

$t'=1.0469\ s$

<u>We observe that </u> $t>t'$ <u> hence the time after the launch of the projectile after which the apple should be tossed is:</u>

$\Delta t=t-t'$

$\Delta t=1.0642-1.0469$

$\Delta t=0.0173\ s$

8 0

3 years ago

What are the difficulties with the capture hypothesis of the Moon’s origin?

Lisa [10]

Answer:

No collision or altered trajectory

Similar percentage of oxygen isotopes

Explanation:

Capture hypothesis states that the Earth captured the moon. This is highly unlikely as such interactions of this type of bodies leads to a collision or their trajectories are altered. The percentage of the oxygen isotopes such as 16O, 17O and 18O in the Moon's basalts are almost identical with Earth. While meteorites have different percentage of oxygen isotopes.

Currently the accepted hypothesis is the giant-impact hypothesis.

5 0

3 years ago