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GuDViN [60]
2 years ago
14

What type of waves move energy forward, but the source makes up and down

Physics
1 answer:
Arturiano [62]2 years ago
7 0
Transverse waves. Direction of vibration of the particles is at right angles to direction of movement.
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Which of the following is a heterogeneous mixture? A. salt B. dye in water C. sugar water D. a garden salad
dedylja [7]
D garden salad : )

A heterogenous mixture can be easily taken apart visually/physically
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2 years ago
The position-time equation for a cheetah chasing an antelope is:
pochemuha

Answer:

x = 1.6 + 1.7 t^2      omitting signs

a) at t = 0     x = 1.6 m

b) V = d x / d t = 3.4 t

at t = 0     V = 0

c) A = d^2 x / d t^2 = 3.4     (at t = 0  A = 3.4 m/s^2)

d)  x = 1.6 + 1.7 * (4.4)^2 = 34.5    (position at 4.4 sec = 34.5 m)

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2 years ago
When a gun is fired at the shooting range, the gun recoils (moves backward). Explain this using the law of conservation of momen
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The total momentum is unchanged according to the law of conservation of momentum. When the gun is fired, the bullet gains a high velocity forward (positive velocity), and that velocity multiplied by its mass is the momentum the bullet gains. Therefore, the gun must gain a momentum backwards to cancel out that momentum forward, so the gun recoils back with a negative velocity.
4 0
2 years ago
Which of these values is equivalent to the change in momentum of
iragen [17]
<span>A. An impulse of a force changes the momentum of a body and has the same units and dimensions as momentum.</span>
3 0
3 years ago
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An infinitely long straight wire has a uniform linear charge density of Derive the 4. equation for the electric field a distance
marshall27 [118]

Answer:

E = \frac{\lambda}{2\pi \epsilon_0 r}

Explanation:

Let the linear charge density of the charged wire is given as

\frac{q}{L} = \lambda

here we can use Gauss law to find the electric field at a distance r from wire

so here we will assume a Gaussian surface of cylinder shape around the wire

so we have

\int E. dA = \frac{q}{\epsilon_0}

here we have

E \int dA = \frac{\lambda L}{\epsilon_0}

E. 2\pi r L = \frac{\lambda L}{\epsilon_0}

so we have

E = \frac{\lambda}{2\pi \epsilon_0 r}

4 0
3 years ago
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