Which of the following is most likely to lose electrons in an ionic compound?
1 answer:
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Explanation:
Apply Boyle's Law :-
P1V1 = P2V2
- Where P1 is 25 atm
- V1 is 3L
- P2 is 75 atm
- V2 is what we need to find out.
25 × 3 = 75 × V2
<u>So, the answer is d) Part, 1L .</u>
Hope it helps :)
Silver-109 has a mass of 109 amu. It is one of the isotopes of the silver atm.
<h3>What are isotopes?</h3>The term isotopes has to do with the atoms of the same element that has the same atomic number but different mass numbers. This implies that the isotopes that we have do have the same number of protons but they do not have the same number of neutrons and the fact that they differ in the number of neutrons implies that would have the same chemical property.
We can see from the question that there are two isotopes of silver and tehse isotopes of silver have been identified as silver-107 and silver-109. The isotopes do have the same mass and not the same number of protons.
The percentage abundance of the two isotopes are not the same which means that one is more than the other. We can now see that the mass of the silver 109 in amu is 109 amu.
Learn more about atomic mass:brainly.com/question/5661976
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