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timama [110]
3 years ago
10

As a real gas deviates from ideal gas behavior, the particles _____

Chemistry
1 answer:
Alik [6]3 years ago
7 0

Answer:

Have some attraction towards each other

Explanation:

Gases deviate from the ideal gas behavior because their molecules have forces of attraction between them. At high pressure, the molecules of gases are very close to each other so the molecular interactions start operating and these molecules do not strike the walls of the container with full impact.

Hope this helps :-)

Have a great rest of your day or night!

Enjoy your studies and assignments

<3 simplysun

ps. I do not own any of these answers so please don't give full credit to me

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What produced the sulfuric acid that helped form the Lechugilla caves
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The answer you need is B. Pollution. Have in mind that Caves contain carvings and depictions that are formed from acids running through the limestones of the cave. The sulfuric acid that helped form the Lechugilla caves come from pollution.I hope this info can help you
7 0
3 years ago
What is the required molarity of a ba(oh)₂ solution to prepare a 1.0 m oh⁻ solution?
timurjin [86]
  The   molarity   of  a  Ba(OH)2  solution  required to prepare   a1.0 OH-  solution  is  calculated  as  follows


write   the  equation  for  dissociation of  Ba(Oh)2


that  is,

Ba(Oh)2  -----> Ba^2+   +  2Oh-

by  use  of  reacting   ratio  between  Ba(Oh)2  to  Oh  which  is   1:2  the  molarity of  Ba(oh)2  =    1.0/2 =  0.5 M
8 0
4 years ago
Read 2 more answers
What is 17.8 + 12.115 in sig fig
iogann1982 [59]

Answer:

Explanation:

17.8 + 12.115 = 29.9

Sig Figs

3

29.9

Decimals

1

29.9

Scientific Notation

2.99 × 10 1

E-Notation

2.99e+1

Words

twenty-nine point nine

4 0
3 years ago
a mixture of gases contains He (g) and Ne (g). the total pressure of the atmosphere in the container is 600 mmHg and the partial
aliina [53]

Answer:

161 mmHg

Explanation:

Ptotal= PHe +PNe

PHe= Ptotal-PNe

PHe= (600 mm Hg)-(439 mmHg)

PHe=161 mmHg

3 0
3 years ago
A solution is prepared by combining 5.00 mL of 4.8x10-4 M NaSCN solution, 2.00 mL of 0.21 M Fe(NO3)3 solution and 13.00 mL of 0.
Tcecarenko [31]

Answer:

The analytical concentrations of thiocyanate ions:

[SCN^-]=0.00012 mol/L

The analytical concentrations of ferric ions:

[Fe^{3+}]=0.063 mol/L

Explanation:

Moles (n)=Molarity(M)\times Volume (L)

1) Moles of sodium thiocyanate  = n

Volume of sodium thiocyanate solution = 5.00 mL = 0.005 L

(1 mL = 0.001L)

Molarity of the sodium thiocyanate = 4.8\times 10^{-4} M

n=4.8\times 10^{-4} M\times 0.005 L=2.4\times 10^{-6}mol

1 mole of sodium thiocyanate has 1 mol of thiocyante ions.

So, moles of thioscyanate ions in 2.4\times 10^{-6}mol  of NaSCN.

=1\times 2.4\times 10^{-6}mol=2.4\times 10^{-6}mol

2) Moles of ferric nitrate = n'

Volume of ferric nitrate solution = 2.00 mL = 0.002 L

Molarity of the ferric nitrate = 0.21 M

n'=0.002 M\times 0.21 L=0.00042 mol

1 mole of ferric nitrate has 3 moles of ferric ions.

So number of moles of ferric ions in 0.00042 moles of ferric nitrate is :

3\times 0.00042 mol=0.00126 mol

Volume of nitric acid = 13.00 mL

Total volume by adding all three volumes of solutions = V

V = 5.00 mL + 2.00 mL + 13.00 mL = 20.00 mL = 0.020 L

The analytical concentrations of thiocyanate ions:

[SCN^-]=\frac{2.4\times 10^{-6}mol}{0.020 L}=0.00012 mol/L

The analytical concentrations of ferric ions:

[Fe^{3+}]=\frac{0.00126 mol}{0.020 L}=0.063 mol/L

3 0
3 years ago
Read 2 more answers
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