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fiasKO [112]
3 years ago
10

Rain falls on a 1346 acre urban watershed at an intensity of 1.75 in/hr for a duration of 1 hour. The catchment land use is 20%

parkland, 30% residential, and 50% multiple detached residential area. The time to concentration is 1 hr. Determine the peak runoff. Use runoff coefficients published in APWA 5600.

Engineering
1 answer:
m_a_m_a [10]3 years ago
3 0

Answer:

Detailed solution is given below:

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Filler metals range in diameter from 1/16" to 3/8"*<br> O<br> true<br> O False
vesna_86 [32]

Answer:

O False

Explanation:

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6 0
2 years ago
Tony works as a Sorter in a processing factory. Which qualifications does he most likely have?
svp [43]

Answer:

answer is B

Explanation:

7 0
2 years ago
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Find the thickness of the material that will allow heat transfer of 6706.8 *10^6 kcal during the 5 months through the rectangle
Vinvika [58]

Answer:

The thickness of the material is 6.23 cm

Explanation:

Given;

quantity of heat, Q = 6706.8 *10⁶ kcal  

duration of the heat transfer, t = 5 months

thermal conductivity of copper, k = 385 W/mk

outside temperature of the heater, T₁ = 30° C

inside  temperature of the heater, T₂ = 50° C

dimension of the rectangular heater = 450 cm by 384 cm

1 kcal = 1.163000 Watt-hour

6706.8 *10⁶ kcal  = 7800008400 watt-hour

I month = 730 hours

5 months = 3650 hours

Rate of heat transfer, P = \frac{7800008400 \ Watt-Hour}{3650 \ Hours}  = 2136988.6 \ W

Rate of heat transfer, P = \frac{K*A *\delta T}{L}

where;

P is the rate of heat transfer (W)

k si the thermal conductivity (W/mk)

ΔT is change in temperature (K)

A is area of the heater (m²)

L is thickness of the heater (m)

P = \frac{KA(T_2-T_1)}{L} \\\\L =  \frac{KA(T_2-T_1)}{P}\\\\L =  \frac{385(4.5*3.84)(50-30)}{2136988.6}\\\\L = 0.0623 \ m

L = 6.23 cm

Therefore, the thickness of the material is 6.23 cm

8 0
2 years ago
Yasir is trying to build an energy-efficient wall and deciding what materials to use. How can he calculate the thermal resistanc
777dan777 [17]

Answer:

Add the thermal R values of each wall layer.

Explanation:

Fiberglass insulation R value, sheetrock, sheathing, siding etc.  All sum together to one composite opposition to heat transfer/loss.

Q= U x A x Delta T

Q= heat transfer btuh

U= 1/R inverse of resistance

A= area of surface

Delta T is temerature difference across the wall.

8 0
3 years ago
In this type of projection, the angles between the three axes are different:- A) Isometric B) Axonometric C) Trimetric D) Dimetn
nekit [7.7K]

Answer:

The correct answer is C) Trimetric

Explanation:

The most suitable answer is a trimetric projection because, in this type of projection, we see that the projection of the three angles between the axes are not equal. Therefore, to generate a trimetric projection of an object, it is necessary to have three separate scales.

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