The pressure drop of air in the bed is 14.5 kPa.
<u>Explanation:</u>
To calculate Re:
From the tables air property
Ideal gas law is used to calculate the density:
ρ = 
ρ = 1.97 Kg / 
ρ = 
R = 
= 8.2 × 
/ 28.97×
R = 2.83 × atm / K Kg
q is expressed in the unit m/s
q = 1.24 m/s
Re = 
Re = 2278
The Ergun equation is used when Re > 10,
= 4089.748 Pa/m
ΔP = 4089.748 × 3.66
ΔP = 14.5 kPa
The answer is 2 because I just took the test!
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