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Serga [27]
4 years ago
5

Zad. 1. Jaką pracę wykona dźwig, który pracował przez 1,5 h napędzany silnikiem o mocy 200 kW?

Physics
1 answer:
Alekssandra [29.7K]4 years ago
7 0

Answer:

Explanation:

1) Moc to wskaźnik czasu pracy w stosunku do czasu.

Moc = czas pracy / czas

Czas pracy = moc * czas

Podana moc = 200 kW = 200 000 Watów

Czas = 1,5 godziny = 1,5 * 3600 = 5400 sekund

workdone = 200 000/5400

Obróbka = 37,04 dżula

2) Moc = Gotowe / czas

Od zakończenia = Siła * Odległość

Moc = siła * Odległość / czas

Podana siła = 300 N.

Odległość = 2,5 m

czas = 0,5 min = 0,5 * 60 = 30 sekund

Moc = 300 * 2,5 / 30

Moc = 25 watów

3) Moc = Gotowe / czas

Czas potrzebny = praca / moc

Biorąc pod uwagę pracę wykonaną przez ciągnik = 10 MJ = 10 * 10 ^ 6 Dżuli

Moc = 100 kW = 100 000 watów

Czas wzięty = 10 ^ 7/10 ^ 5

Zajęty czas = 100 sekund

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Answer:

A dominant allele produces a dominant trait in individuals who have one copy of the allele, that can come from one parent. To produces a recessive trait, the child must have two copies of the recessive allele, one from each parent.

Explanation:

The terms dominant and recessive describe the patterns of certain traits. They describe how likely it is for certain traits to pass from parent offspring in humans and animals. The two copies of each gene (alleles), can be slightly different from each other. The differences can cause variations in the protein that’s produced, Proteins affect traits, so variations in protein activity or expression can create different phenotypes.

A dominant allele produces a dominant phenotype (trait) in individuals who have one copy of the allele, which can come from one parent. For a recessive allele to produce a recessive phenotype, the individual must have two copies, one from each parent. A person with one dominant and one recessive allele for a gene will have a dominant phenotype. They are generally considered carriers of the recessive allele- the recessive allele is there, but the recessive phenotype is not.

8 0
3 years ago
2. A box filled with books has a mass of 15.0 kg. It is pushed across the floor with a constant force of 60.0 N. If the friction
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Answer:

3 m/s^{2}

Explanation:

ΣF=ma

The two forces at play are the force applied and the force due to friction. As they are opposing forces set the direction being pushed as the positive in the x direction. the equation you come out with is 60 - 15=(15)A (we know mass to be 15kg). Solve for 3 m/s^2.

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An expert archer tried to shoot an arrow into a target lying at the bottom of a shallow pool. Even though the water did not chan
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The interaction that caused the archer to miss was probably refraction.
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3 years ago
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Find the distance between the points (2, 8) and (-1, 9).
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The approximate value for the distance between the two points is <span>3.162277663.16227766</span>.

<span><span>√10</span>≈<span>3.16227766

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A parallel-plate air capacitor is made from two plates 0.190 m square, spaced 0.770 cm apart. It is connected to a 120 V battery
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Answer:

aaksj

Explanation:

a) the capacitance is given of a plate capacitor is given by:

C = \epsilon_0*(A/d)

Where \epsilon_0 is a constant that represents the insulator between the plates (in this case air, \epsilon_0 = 8.84*10^(-12) F/m), A is the plate's area and d is the distance between the plates. So we have:

The plates are squares so their area is given by:

A = L^2 = 0.19^2 = 0.0361 m^2

C = 8.84*10^(-12)*(0.0361/0.0077) = 8.84*10^(-12) * 4.6883 = 41.444*10^(-12) F

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c) The electric field on a capacitor is given by:

E = Q/(A*\epsilon_0) = [4.973*10^(-9)]/[0.0361*8.84*10^(-12)]

E = [4.973*10^(-9)]/[0.3191*10^(-12)] = 15.58*10^(3) V/m

d) The energy stored on the capacitor is given by:

W = 0.5*(C*V^2) = 0.5*[41.444*10^(-12) * (120)^2] = 298396.8*10^(-12) = 0.298 * 10 ^6 J

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