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muminat
3 years ago
11

IS THIS CORRECT???...........................

Physics
1 answer:
never [62]3 years ago
8 0

Answer:

<u><em>A. consumers</em></u>

<u><em>B. multi-cellular</em></u>

Explanation:

Only plants have chlorophyll and only plants have a cell wall so C and D are out of the window. They are consumers because, they don't have photosynthesis so they have to eat. They are multi-cellular because, animals all have at least a brain, body, etc. Which all need millions of cells.

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A 200 g block is pressed against a spring of force constant 1.40 kN/m until the block compresses the spring 10.0 cm. The spring
tino4ka555 [31]

Answer:

Explanation:

This problem bothers on the energy stored in a spring in relation to conservation of energy

Given data

Mass of block m =200g

To kg= 200/1000= 0.2kg

Spring constant k = 1.4kN/m

=1400N/m

Compression x= 10cm

In meter x=10/100 = 0.1m

Using energy considerations or energy conservation principles

The potential energy stored in the spring equals the kinetic energy with which the block move away from the spring

Potential Energy stored in spring

P.E=1/2kx^2

Kinetic energy of the block

K.E =1/mv^2

Where v = velocity of the block

K.E=P.E (energy consideration)

1/2kx^2=1/mv^2

Kx^2= mv^2

Solving for v we have

v^2= (kx^2)/m

v^2= (1400*0.1^2)/0.2

v^2= (14)/0.2

v^2= 70

v= √70

v= 8.36m/s

a. Distance moved if the ramp exerts no force on the block

Is

S= v^2/2gsinθ

Assuming g= 9. 81m/s^2

S= (8.36)^2/2*9.81*sin60

S= 69.88/19.62*0.866

S= 69.88/16.99

S= 4.11m

6 0
3 years ago
To water the yard you use a hose with a diameter of 3.2 cm. Water flows from the hose with a speed of 1.1 m/s. If you partially
cupoosta [38]

Answer:

The speed of water flow inside the pipe at point - 2 = 34.67 m / sec

Explanation:

Given data

Diameter at point - 1 = 3.2 cm

Velocity at point - 1 = 1.1 m / sec = 110 cm / sec

Diameter at point - 2 = 0.57 cm

Velocity at point - 2 = ??

We know that from the continuity equation the rate of flow is constant inside  a pipe between two points.

Thus

⇒ A_{1} × V_{1} = A_{2} × V_{2}

⇒  \frac{\pi }{4} × d_{1} ^{2} × V_{1} =

⇒  d_{1} ^{2} × V_{1} =  d_{2} ^{2}  × V_{2}

⇒  (3.2)^{2} × 110 = (0.57)^{2} × V_{2}

⇒ V_{2} = 3467 cm / sec

⇒ V_{2} = 34.67 m / sec  

Thus the speed of water flow inside the pipe at point - 2 = 34.67 m / sec

3 0
3 years ago
If a new star appeared in our solar system that was larger and heavier than the Sun, the planets would MOST LIKELY A) orbit the
s344n2d4d5 [400]
D. since the star would be larger than the sun, having more mass, its gravitational pull would be stronger thus pulling the planets into it. hope that helped!
7 0
4 years ago
Read 2 more answers
How do you measure the amount of energy something has?
shtirl [24]

Answer:

The official measurement unit for energy is the Joule (J). Among the most common units measuring energy mention should be made of the kilowatt/hour (kWh), used especially for electric energy (in fact it is used to calculate electricity bills).

Explanation:

5 0
3 years ago
The surface area of the earth's crust is 5.10*10^8km^2. The average thickness of the earth's crust is 35km. The mean density of
Mars2501 [29]

Answer:

The answer is V = 1.785 \times 10^{10}\ Km^3.

Explanation:

You are asking only for the total volume, so the important data here is the surface area of the earth's crust,

A = 5.10 \times 10^8\ Km^2

and the average thickness of the earth's crust,

h = 35\ Km.

Imagine that you can stretch the surface area as if it were a blanket, now if you want to calculate its volume, you just need to multiply its area by its thickness,

V = A*h = 1.785 \times 10^{10}\ Km^3.

4 0
3 years ago
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