Answer:
Explanation:
This problem bothers on the energy stored in a spring in relation to conservation of energy
Given data
Mass of block m =200g
To kg= 200/1000= 0.2kg
Spring constant k = 1.4kN/m
=1400N/m
Compression x= 10cm
In meter x=10/100 = 0.1m
Using energy considerations or energy conservation principles
The potential energy stored in the spring equals the kinetic energy with which the block move away from the spring
Potential Energy stored in spring
P.E=1/2kx^2
Kinetic energy of the block
K.E =1/mv^2
Where v = velocity of the block
K.E=P.E (energy consideration)
1/2kx^2=1/mv^2
Kx^2= mv^2
Solving for v we have
v^2= (kx^2)/m
v^2= (1400*0.1^2)/0.2
v^2= (14)/0.2
v^2= 70
v= √70
v= 8.36m/s
a. Distance moved if the ramp exerts no force on the block
Is
S= v^2/2gsinθ
Assuming g= 9. 81m/s^2
S= (8.36)^2/2*9.81*sin60
S= 69.88/19.62*0.866
S= 69.88/16.99
S= 4.11m
Answer:
The speed of water flow inside the pipe at point - 2 = 34.67 m / sec
Explanation:
Given data
Diameter at point - 1 = 3.2 cm
Velocity at point - 1 = 1.1 m / sec = 110 cm / sec
Diameter at point - 2 = 0.57 cm
Velocity at point - 2 = ??
We know that from the continuity equation the rate of flow is constant inside a pipe between two points.
Thus
⇒
×
=
× 
⇒
×
×
=
⇒
×
=
× 
⇒
× 110 =
× 
⇒
= 3467 cm / sec
⇒
= 34.67 m / sec
Thus the speed of water flow inside the pipe at point - 2 = 34.67 m / sec
D. since the star would be larger than the sun, having more mass, its gravitational pull would be stronger thus pulling the planets into it. hope that helped!
Answer:
The official measurement unit for energy is the Joule (J). Among the most common units measuring energy mention should be made of the kilowatt/hour (kWh), used especially for electric energy (in fact it is used to calculate electricity bills).
Explanation:
Answer:
The answer is
.
Explanation:
You are asking only for the total volume, so the important data here is the surface area of the earth's crust,

and the average thickness of the earth's crust,
.
Imagine that you can stretch the surface area as if it were a blanket, now if you want to calculate its volume, you just need to multiply its area by its thickness,
.