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julsineya [31]
3 years ago
11

What volume of 15.6M NH4OH is needed to make 500. mL of 3.00M solution?

Chemistry
1 answer:
Mariana [72]3 years ago
6 0

Answer:

V₁  = 96.2 mL

Explanation:

Given data:

Initial volume of NH₄OH required = ?

Initial molarity = 15.6 M

Final molarity = 3.00 M

Final volume = 500.0 mL

Solution:

Formula:

M₁V₁  =  M₂V₂

M₁ = Initial molarity

V₁  =  Initial volume of NH₄OH

M₂ =Final molarity

V₂ = Final volume

Now we will put the values.

15.6 M ×V₁  =  3.00 M×500.0 mL

15.6  M ×V₁  = 1500 M.mL

V₁  = 1500 M.mL /15.6 M

V₁  = 96.2 mL

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ira [324]

A carboxyl group is present in 6-chlorohexanoic acid having IR peak between 1690 -1760 Cm-1 whereas in 4-methoxypentanoyl chloride , a carbonyl group is present as oyl chloride as having peak between 1715 -1745 Cm-1.

Now, in 4-methoxypentanoyl chloride , the peaks are (1 H, m) , (2 H, t ), (2 H , q ) whereas in 6-chlorohexanoic acid , the peaks are (2 H, m), (2 H, m ), (2 H , t )

3 0
3 years ago
What is the mass of 3.01 X 1023 atoms of iron? (atomic mass of Fe=56)
anyanavicka [17]
84280/3011 or 27.9907g Fe

Explanation:

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3 0
3 years ago
Please I’m skipping math and Ela for this help
NikAS [45]

Answer:

c

Explanation:

because it is c ok ????????????

4 0
3 years ago
Name the functional group in the
zysi [14]

Answer:

the correct answer B. carboxylic acid

Explanation:

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6 0
2 years ago
2H2 + O2 → 2H2O
pantera1 [17]
Okay
Mr (H2O)= 18g
therefore moles of H2O
is 720.8/18= 40.04mol
the ratio of H2 to O2 to H2O is
2 : 1 : 2
so moles of H2 is same as H2O here
H2= 40.04moles

moles of O2 is half
so 40.04 x 0.5
20.02moles

grams of O2 is
its moles into Mr of O2
that's 20.02 x 32 = 640.64g

6 0
3 years ago
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