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julsineya [31]
3 years ago
11

What volume of 15.6M NH4OH is needed to make 500. mL of 3.00M solution?

Chemistry
1 answer:
Mariana [72]3 years ago
6 0

Answer:

V₁  = 96.2 mL

Explanation:

Given data:

Initial volume of NH₄OH required = ?

Initial molarity = 15.6 M

Final molarity = 3.00 M

Final volume = 500.0 mL

Solution:

Formula:

M₁V₁  =  M₂V₂

M₁ = Initial molarity

V₁  =  Initial volume of NH₄OH

M₂ =Final molarity

V₂ = Final volume

Now we will put the values.

15.6 M ×V₁  =  3.00 M×500.0 mL

15.6  M ×V₁  = 1500 M.mL

V₁  = 1500 M.mL /15.6 M

V₁  = 96.2 mL

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Answer:

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Amount of oxygen left  = 0.035 mol

Explanation:

Masa of ammonia = 2.00 g

Mass of oxygen = 4.00 g

Which is limiting reactant = ?

Balance chemical equation:

4NH₃ + 3O₂     →     2N₂ + 6H₂O

Number of moles of ammonia:

Number of moles = mass/molar mass

Number of moles = 2.00 g/ 17 g/mol

Number of moles = 0.12 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

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Number of moles = 0.125 mol

Now we will compare the moles of ammonia and oxygen with water and nitrogen.

                      NH₃          :            N₂

                        4             :             2

                      0.12           :           2/4×0.12 = 0.06

                      NH₃         :            H₂O

                        4            :             6

                        0.12       :           6/4×0.12 = 0.18

                       

                       O₂            :            N₂

                        3             :             2

                      0.125        :           2/3×0.125 = 0.08

                        O₂           :            H₂O

                        3              :             6

                        0.125       :           6/3×0.125 = 0.25

The number of moles of water and nitrogen formed by ammonia are less thus ammonia will be limiting reactant.

Amount of oxygen left:

                        NH₃          :             O₂

                           4            :              3

                           0.12       :          3/4×0.12= 0.09

Amount of oxygen react = 0.09 mol

Amount of oxygen left  = 0.125 - 0.09 = 0.035 mol

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<u>Answer:</u> The balanced chemical equation for the decomposition of nitroglycerin is written below.

<u>Explanation:</u>

Decomposition reaction is defined as the reaction in which a single large substance breaks down into two or more smaller substances.

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A balanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is equal to the total number of individual atoms on product side.

The balanced chemical equation for the decomposition of nitroglycerin follows:

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