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the amount of heat required to increase the temperature of 1 gram by 1°C
Explanation:
The specific heat of a substance is the amount of heat required to increase the temperature of 1 gram of a substance by 1°C. It is an intensive property that is specific to every substance.
The unit is given as J/g⁻¹°C⁻¹ or J/g⁻¹K⁻¹
This related to the quantity of heat using the expression below:
Q = mC∅
Q is the quantity of heat added
m is the mass
C is the specific heat
∅ is the temperature change.
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Answer:
Option(II) and option (IV) are correct.
Explanation:
Here products are 
and 
and reactant is 
(I) According to Le-chatelier principle,increase in will shift the equilibrium towards reactant side to keep the equilibrium constant unchanged.
(II) According to Le-chatelier principle,decrease in will shift the equilibrium towards product side to keep the equilibrium constant unchanged.
(III) Adding a catalyst will not change position of equilibrium. Catalyst only helps to achieve equilibrium in a lesser time.
(IV) As this reaction is an endothermic reaction therefore heat is consumed in formation of product. Therefore increase in temperature will lead to formation of more product to consume excess heat added.
(V) Pure solids and liquids do not affect position of equilibrium as their concentrations remain unchanged.
Answer:
A. Precipitate reaction
Explanation:
The types of reactions are (1) combination or synthesis reactions. (2) decomposition reactions. (3) substitution or single replacement reactions. (4) metathesis or double displacement reactions
Answer:
The fire may grow bigger, depending on the gas.
Explanation:
If you expose more air to a small flame then it could grow larger because air keeps fire alive.
<u>We are given:</u>
Volume of gas = 3.8 L
Pressure = 460 mmHg
Temperature = 77°c = (77+273)K = 350K
<u>Converting the pressure to atm:</u>
Pressure(in atm) = Pressure(in mmHg) / 760
Pressure = 460/760 = 0.6 atm
<u>Finding the number of moles:</u>
using the ideal gas equation:
PV = nRT [where R is the universal gas constant]
<em>replacing the given values in this equation</em>
(0.6)(3.8) = n(0.082)(350)
n = (0.6*3.8)/(0.082*350)
n = 0.08 moles
