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Rina8888 [55]
3 years ago
10

Please help me the picture is above, I’ll mark as brainliest.

Chemistry
1 answer:
salantis [7]3 years ago
3 0
Carbon dioxide 100% x
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What is Acceleration?​
Lerok [7]

in per unit time some things velocity changes rate is called acceleration

3 0
3 years ago
How many electrons in an atom can have each of the following quantum number or sublevel designations?
storchak [24]

10 electrons in an atom can have each of the 3d quantum number or sublevel designations.

<h3>What are four quantum numbers?</h3>

Quantum numbers are used to characterize the values of conserved quantities in a quantum system's dynamics in both quantum physics and chemistry.

1) The "n" sign refers to the principal quantum number. It shows how many shells there are.

2) The "l" sign indicates the azimuthal quantum number. It gives the form of the orbitals and their angular momentum. 0 to n-1 make up its range.

3) "m_{l}" stands for the magnetic quantum number. It serves as a cue for spatial orientation. The range of it is -l to +l.

4) Spin quantum number, represented by the symbol "m_{s}". It shows how the electron is spinning.

Learn more about quantum numbers here:

brainly.com/question/14288557

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4 0
2 years ago
Use the chart to determine which type of bond is formed between potassium (K) and chlorine (Cl).
iris [78.8K]
Potassium and Chloride forms an ionic bond.
(K+) + (Cl-) = KCl

Potassium is under Group IA (Alkali Metal), wherein elements under this group can easily lose electrons.

Chlorine is under Group VII (Halogens), in which these elements can gain electrons easily.

The inner shell electrons on potassium will merge with the outer shell of electrons of chlorine to make potassium chloride.
6 0
4 years ago
Read 2 more answers
How do you answer number 3
Mice21 [21]

Answer:

simple, multiply by 23

Explanation:

23x102=827117

5 0
4 years ago
The temperature of a sample of iron with a mass of 10.0 g changed from 50.4°C to 25.0°C with the release of 47 calories of heat.
hichkok12 [17]
Q  =  mc(θ₂-θ₁)

47 calories =  10 g *c*(50.4 - 25)

47cal = 10*c* 25.4

47 /(10*25.4) = c

0.185 = c

Specific heat of iron = 0.185 cal/g°C 
5 0
3 years ago
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