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Rus_ich [418]
2 years ago
10

When coal burns, the reaction

Chemistry
1 answer:
katovenus [111]2 years ago
4 0
Answer is B. Releases heat and is exothermic
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Mention 4 products formed formed from destructive distillation of coal
LenaWriter [7]

coal gas, gas carbon, coal tar and ammonia liquor,

5 0
3 years ago
Read 2 more answers
If 3.0 moles of x and 4.0 moles of y react according to the hypothetical reaction below, how many moles of the excess reactant w
Lesechka [4]
Firstly the limiting reactant should be identified. Limiting reactant is the reactant that is in limited supply, the amount of product formed depends on the moles present of the limiting reactant.

the stoichiometry of x to y = 1:2
1 mole of x reacts with 2 moles of y
if x is the limiting reactant, there are 3 moles of x, then 6 moles of y should react, however there are only 4 moles of y. Therefore y is the limiting reactant and x is in excess.
4 moles of y reacts with 2 moles of x 
since there are 3 moles of x initially and only 2 moles are used up, excess amount of x is 1 mol thats in excess.


6 0
2 years ago
Just wanted to make sure I have the right idea.
Rasek [7]

Explanation:

yes you got the right idea

4 0
3 years ago
Whats is not a characteristic of the eye of a hurricane
Marina86 [1]

B. has the storms strongest winds is not a characteristic of the eye of a hurricane because in the eye it is actually completely calm.

Hope that helps u!!

5 0
3 years ago
Read 2 more answers
A sample of vinegar was found to have an acetic acid concentration of 0.8846 m. What is the acetic acid % by mass? Assume the de
jenyasd209 [6]

Answer:

5.3%

Explanation:

Let the volume be 1 L

volume , V = 1 L

use:

number of mol,

n = Molarity * Volume

= 0.8846*1

= 0.8846 mol

Molar mass of CH3COOH,

MM = 2*MM(C) + 4*MM(H) + 2*MM(O)

= 2*12.01 + 4*1.008 + 2*16.0

= 60.052 g/mol

use:

mass of CH3COOH,

m = number of mol * molar mass

= 0.8846 mol * 60.05 g/mol

= 53.12 g

volume of solution = 1 L = 1000 mL

density of solution = 1.00 g/mL

Use:

mass of solution = density * volume

= 1.00 g/mL * 1000 mL

= 1000 g

Now use:

mass % of acetic acid = mass of acetic acid * 100 / mass of solution

= 53.12 * 100 / 1000

= 5.312 %

≅ 5.3%

3 0
3 years ago
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