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fgiga [73]
2 years ago
8

Identify the vertex and axis of symmetry. f(x) = 3(x+7)²-5

Mathematics
2 answers:
Verizon [17]2 years ago
5 0

Answer:

haiii i can only solve for the vertex...

Step-by-step explanation:

so to find the vertex you have to make it to

y - h = a(x - k)^2

i think

(you could also just make it y = a(x - k)^2 + h but i like the second one better)

soo

y + 5 = 3(x + 7)^2

the vertex is

(-7, -5)

and ummm i think the axis for the axis of symmetry .ss

x = 2a/b but im not sure

masha68 [24]2 years ago
5 0
(-7,-5) i am pretty sure if not i’m sorry
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Find the area of the rhombus.<br> 4.32 m2<br> 2.16 m2<br> 1.08 m2<br> 1.05 m2
S_A_V [24]

Answer:

Step-by-step explanation:

Alright, lets get started.

The part of the diagonals are given as 0.9 m and 1.2 m.

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Hence the length of diagonals will be : 0.9*2=1.8 and 1.2*2=2.4

The formula of area of rhombus is : \frac{pq}{2} where p and q are the length of diagonals.

So plugging the values of diagonals in formula, the area will be :

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3 years ago
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3 years ago
Guys help please I am struggling
alina1380 [7]

9514 1404 393

Answer:

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Step-by-step explanation:

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Now we take logarithms to make this a linear equation.

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Answer:

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Read 2 more answers
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