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WITCHER [35]
3 years ago
15

H(x)=-(x+11)^2+1. What are the zeros of the function? What is the vertex of the parabola?

Mathematics
1 answer:
Nataly_w [17]3 years ago
8 0

Answer:

x=-14

Step-by-step explanation:

-x-11^2+1

-x-11^3

-x^14

x=-14

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Clara writes the equation (x – 13)(x + 8) = 196 to solve for the missing side length of a triangle represented by the factor x +
Kitty [74]
<span>(x – 13)(x + 8) = 196
</span>x * x + x * 8 - 13 * x - 13 * 8 = 196
x² + 8x - 13x - 104 = 196
x² - 5x - 104 - 196 = 0
x² - 5x - 300 = 0

The missing side length is 28

3 0
3 years ago
Vusi makes bead bracelets in different designs. The first design uses 23 beads, the second design uses 29 beads and the third de
sergey [27]

When the remainder theorem is applied to the total number of beads, the number of beads left is 3

<h3>What is remainder theorem?</h3>

The question is an illustration of remainder theorem. Remainder theorem is used to determine the remainder when a number divides another

The number of beads used in each design are given as:

First = 23

Second = 29

Third = 31

Calculate the total number of beads used for all three designs

Total =First + Second + Third

Total =23 + 29 + 31

Total =83

The number of available beads is:

Available = 750

Divide 750 by 83, to get the total number of designs

n = \frac{750}{83}

n =9.03

Remove decimal (do not approximate)

n = 9

The number of beads remaining is calculated using:

Remaining =Available -n \times Total

Remaining =750 -9 \times 83

Remaining =3

Hence, there are 3 beads remaining

Read more about remainder theorem at:

brainly.com/question/13328536

7 0
2 years ago
I how do I do this ?!??
stiv31 [10]

Answer:

m = -3/2 and b = 4

Step-by-step explanation:

m = slope and u go down 3 and over 2 so its -3/2

b = your y intercept and its intercepting through 4 on the y-axis

5 0
3 years ago
At Al's Pizza, 57% of the orders included pepperoni pizza. At World's Best Pizza, 11 out of 19 orders included pepperoni pizza.
a_sh-v [17]

100-57=47% at Als pizza

11/19*100=57.9% at wold best

Therefore world best make greater %

5 0
3 years ago
What are the possible numbers of positive, negative, and complex zeros of
o-na [289]
Answer:

Look at changes of signs to find this has <span>1 </span> positive zero, <span>1 </span> or <span>3 </span> negative zeros and <span>0 </span> or <span>2 </span> non-Real Complex zeros.

Then do some sums...

Explanation:

<span><span><span>f<span>(x)</span></span>=−3<span>x4</span>−5<span>x3</span>−<span>x2</span>−8x+4</span> </span>

Since there is one change of sign, <span><span>f<span>(x)</span></span> </span> has one positive zero.

<span><span><span>f<span>(−x)</span></span>=−3<span>x4</span>+5<span>x3</span>−<span>x2</span>+8x+4</span> </span>

Since there are three changes of sign <span><span>f<span>(x)</span></span> </span> has between <span>1 </span> and <span>3 </span> negative zeros.

Since <span><span>f<span>(x)</span></span> </span> has Real coefficients, any non-Real Complex zeros will occur in conjugate pairs, so <span><span>f<span>(x)</span></span> </span> has exactly <span>1 </span> or <span>3 </span> negative zeros counting multiplicity, and <span>0 </span> or <span>2 </span> non-Real Complex zeros.

<span><span>f'<span>(x)</span>=−12<span>x3</span>−15<span>x2</span>−2x−8</span> </span>

Newton's method can be used to find approximate solutions.

Pick an initial approximation <span><span>a0</span> </span>.

Iterate using the formula:

<span><span><span>a<span>i+1</span></span>=<span>ai</span>−<span><span>f<span>(<span>ai</span>)</span></span><span>f'<span>(<span>ai</span>)</span></span></span></span> </span>

Putting this into a spreadsheet and starting with <span><span><span>a0</span>=1</span> </span> and <span><span><span>a0</span>=−2</span> </span>, we find the following approximations within a few steps:

<span><span><span>x≈0.41998457522194</span> </span><span><span>x≈−2.19460208831628</span> </span></span>

We can then divide <span><span>f<span>(x)</span></span> </span> by <span><span>(x−0.42)</span> </span> and <span><span>(x+2.195)</span> </span> to get an approximate quadratic <span><span>−3<span>x2</span>+0.325x−4.343</span> </span> as follows:

Notice the remainder <span>0.013 </span> of the second division. This indicates that the approximation is not too bad, but it is definitely an approximation.

Check the discriminant of the approximate quotient polynomial:

<span><span><span>−3<span>x2</span>+0.325x−4.343</span> </span><span><span><span>Δ=<span>b2</span>−4ac=<span>0.3252</span>−<span>(4⋅−3⋅−4.343)</span>=0.105625−52.116=</span><span>−52.010375</span></span> </span></span>

Since this is negative, this quadratic has no Real zeros and we can be confident that our original quartic has exactly <span>2 </span> non-Real Complex zeros, <span>1 </span> positive zero and <span>1 </span> negative one.

3 0
3 years ago
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