H(x)=-(x+11)^2+1. What are the zeros of the function? What is the vertex of the parabola?

Clara writes the equation (x – 13)(x + 8) = 196 to solve for the missing side length of a triangle represented by the factor x +

Kitty [74]

(x – 13)(x + 8) = 196
x * x + x * 8 - 13 * x - 13 * 8 = 196
x² + 8x - 13x - 104 = 196
x² - 5x - 104 - 196 = 0
x² - 5x - 300 = 0

The missing side length is 28

3 0

3 years ago

Vusi makes bead bracelets in different designs. The first design uses 23 beads, the second design uses 29 beads and the third de

sergey [27]

When the remainder theorem is applied to the total number of beads, the number of beads left is 3

<h3>What is remainder theorem?</h3>

The question is an illustration of remainder theorem. Remainder theorem is used to determine the remainder when a number divides another

The number of beads used in each design are given as:

$First = 23$

$Second = 29$

$Third = 31$

Calculate the total number of beads used for all three designs

$Total =First + Second + Third$

$Total =23 + 29 + 31$

$Total =83$

The number of available beads is:

$Available = 750$

Divide 750 by 83, to get the total number of designs

$n = \frac{750}{83}$

$n =9.03$

Remove decimal (do not approximate)

$n = 9$

The number of beads remaining is calculated using:

$Remaining =Available -n \times Total$

$Remaining =750 -9 \times 83$

$Remaining =3$

Hence, there are 3 beads remaining

Read more about remainder theorem at:

brainly.com/question/13328536

7 0

2 years ago

I how do I do this ?!??

stiv31 [10]

Answer:

m = -3/2 and b = 4

Step-by-step explanation:

m = slope and u go down 3 and over 2 so its -3/2

b = your y intercept and its intercepting through 4 on the y-axis

5 0

3 years ago

At Al's Pizza, 57% of the orders included pepperoni pizza. At World's Best Pizza, 11 out of 19 orders included pepperoni pizza.

a_sh-v [17]

100-57=47% at Als pizza

11/19*100=57.9% at wold best

Therefore world best make greater %

5 0

3 years ago

What are the possible numbers of positive, negative, and complex zeros of

o-na [289]

Answer:

Look at changes of signs to find this has 1 positive zero, 1 or 3 negative zeros and 0 or 2 non-Real Complex zeros.

Then do some sums...

Explanation:

f(x)=−3x4−5x3−x2−8x+4

Since there is one change of sign, f(x) has one positive zero.

f(−x)=−3x4+5x3−x2+8x+4

Since there are three changes of sign f(x) has between 1 and 3 negative zeros.

Since f(x) has Real coefficients, any non-Real Complex zeros will occur in conjugate pairs, so f(x) has exactly 1 or 3 negative zeros counting multiplicity, and 0 or 2 non-Real Complex zeros.

f'(x)=−12x3−15x2−2x−8

Newton's method can be used to find approximate solutions.

Pick an initial approximation a0 .

Iterate using the formula:

ai+1=ai−f(ai)f'(ai)

Putting this into a spreadsheet and starting with a0=1 and a0=−2 , we find the following approximations within a few steps:

x≈0.41998457522194 x≈−2.19460208831628

We can then divide f(x) by (x−0.42) and (x+2.195) to get an approximate quadratic −3x2+0.325x−4.343 as follows:

Notice the remainder 0.013 of the second division. This indicates that the approximation is not too bad, but it is definitely an approximation.

Check the discriminant of the approximate quotient polynomial:

−3x2+0.325x−4.343 Δ=b2−4ac=0.3252−(4⋅−3⋅−4.343)=0.105625−52.116=−52.010375

Since this is negative, this quadratic has no Real zeros and we can be confident that our original quartic has exactly 2 non-Real Complex zeros, 1 positive zero and 1 negative one.

3 0

3 years ago