Answer:
A student can predict Amount of calories present if she finds the mass of whole candy bar,including the wrapper.
<u>Explanation:</u>
Based on the mass of a whole candy bar a student can predict the calories contained in the candy bar. If the mass of candy bar is more than it means it has more calories and if the candy bar has less mass than it shows the presence of fewer calories.
More calories mean more sugar content in the candy bar. With sugar, the candy bar has carbohydrates also. The sugar present in the bar gives us energy.
Answer:
1. It is a covalent bond and all covalent bonds have low melting points
Explanation:
The Number of moles required for MTBE is 2 as per molarity based chemistry theories.
- A flammable liquid with a distinct, unpleasant smell is called methyl tert-butyl ether (MTBE).
- Since the 1980s, it has been added to unleaded gasoline as a fuel additive to promote more effective burning.
- It is created by mixing chemicals like isobutylene and methanol. Gallstones can be removed with MTBE as well.
- In this type of treatment, surgically inserted special tubes are used to deliver MTBE directly to the gall bladders of the patients.
- Methyl tert-butyl ether is a colorless liquid with a distinct anesthetic-like smell. Vapors are narcotic and heavier than air. 131 °F boiling point. 18 °F is the flash point.
- It is miscible in water and less dense than water. Boosts the octane of gasoline.
- Therefore it has 2 moles of oxygen.
To study about isobutylene -
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The concentration of the zinc acetate, Zn(C₂H₃O₂) solution is 1.067 M
- We'll begin by calculating the number of mole in 20.5 g of Zn(C₂H₃O₂)₂
Mass of Zn(C₂H₃O₂)₂ = 20.5 g
Molar mass of Zn(C₂H₃O₂)₂ = 65 + 2[(12×2) + (3×1) + (16×2)]
= 65 + 2[59]
= 183 g/mol
<h3>Mole of Zn(C₂H₃O₂)₂ =? </h3>
Mole = mass / molar mass
Mole of Zn(C₂H₃O₂)₂ = 20.5 / 183
<h3>Mole of Zn(C₂H₃O₂)₂ = 0.112 mole </h3>
- Finally, we shall determine concentration of Zn(C₂H₃O₂). This can be obtained as follow:
Mole of Zn(C₂H₃O₂)₂ = 0.112 mole
Volume = 105 mL = 105 / 1000 = 0.105 L
<h3>Concentration of Zn(C₂H₃O₂)₂ =? </h3>
Concentration = mole / Volume
Concentration of Zn(C₂H₃O₂)₂ = 0.112 / 0.105
<h3>Concentration of Zn(C₂H₃O₂)₂ = 1.067 M</h3>
Therefore, the concentration of the zinc acetate, Zn(C₂H₃O₂) solution is 1.067 M
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