<span>inorganic
Let's look at the choices and see why they work, or don't work.
monosaccharide
* Otherwise known as a simple sugar. And NaCl is definitely not a sugar of any type. So this is wrong.
disaccharide
* Complex sugar. And NaCl doesn't qualify either.
organic
* A definition of an organic compound is one that has carbon in it. NaCl has sodium and chlorine. No carbon at all, so this isn't the right answer. And I wish that organic was an earlier choice, since the sugars mentioned above are organic compounds.
inorganic
* This is the only possible choice. Salt is not an organic compound since it doesn't have carbon. So it can't be a sugar either. But it can and is inorganic.</span>
Bronze metal is harder and more malleable than copper. It is also conducts property of ductility, so it can be easily shaped as a statue.
Answer: M-18
Explanation:
The mass spectra of alcohols often fail to exhibit detectable M peaks but instead show relatively large __M-18___ peaks.
Mass spectroscopy is used to determine the molecular mass and molecular formula of a sample.
When the mass spectra of alcohols do not show detectable M peaks, they show relatively large M-18 peaks.
<span>Answer: 0.094%
</span><span>Explanation:
</span>
<span></span><span /><span>
1) Equilibrium chemical equation:
</span><span />
<span>Only the ionization of the formic acid is the important part.
</span><span />
<span>HCOOH(aq) ⇄ HCOO⁻(aq) + H⁺(aq).
</span><span />
<span>2) Mass balance:
</span><span />
<span> HCOOH(aq) HCOO⁻(aq) H⁺(aq).
Start 0.311 0.189
Reaction - x +x +x
Final 0.311 - x 0.189 + x x
3) Acid constant equation:
</span><span />
<span>Ka = [HCOO-] [N+] / [HCOOH] = (0.189 + x) x / (0.311 -x)
</span><span />
<span>= (0.189 + x )x / (0.311 - x) = 0.000177
4) Solve the equation:
You can solve it exactly (it will lead to a quadratic equation so you can use the quadratiic formula). I suggest to use the fact that x is much much smaller than 0.189 and 0.311.
</span><span />
<span>With that approximation the equation to solve becomes:
</span><span>0.1890x / 0.311 = 0.000177, which leads to:</span>
<span /><span>
x = 0.000177 x 0.311 / 0.189 = 2.91 x 10⁻⁴ M
5) With that number, the percent of ionization (alfa) is:
</span><span />
<span>percent of ionization = (moles ionized / initial moles) x 100 =
</span><span>
</span><span>
</span><span>percent ionization = (concentration of ions / initial concentration) x 100 =
</span><span>
</span><span>
</span><span>percent ionization = (0.000291 / 0.311)x 100 = 0.0936% = 0.094%
</span>
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