There are 3 atoms found in one molecules of
We will take that molar mass of Pb(CO3)2 represents the total mass of all particles in this compound, ie it has value 100%.
M(Pb(CO3)2) = Ar(Pb) + 2xAr(C) + 6xAr(O) = 207.2 + 2x12 + 6x16= 327.2 g/mol
M(Pb) = 207.2 g/mol
From the date above we can set the following ratio:
M(Pb(CO3)2) : M(Pb) = 100% : x
327.2 : 207.2 = 100 :x
x = 63.33% of Pb there is in <span>Pb(Co3)2</span>
When the number of electron and number of protons are equal in the atom then the atom is said to be an electrically neutral atom. The loss of electron will result in the formation of cation and the atom will possess positive charge which is equal to the number of electrons lost whereas the gain of electron will result in the formation of anion and the atom will possess negative charge which is equal to the number of electrons gained.
The electrically neutral atom have 0 charge as the number of protons and electrons are equal.
For electrically neutral atom of hydrogen, the number of electron =1 and the number of proton = 1.
Hence, the charge on an electrically neutral atom of hydrogen is 0.
Answer: The empirical formula for the given compound is
Explanation : Given,
Percentage of C = 84.4 %
Percentage of H = 15.6 %
Let the mass of compound be 100 g. So, percentages given are taken as mass.
Mass of C = 84.4 g
Mass of H = 15.6 g
To formulate the empirical formula, we need to follow some steps:
Step 1: Converting the given masses into moles.
Moles of Carbon =
Moles of Hydrogen =
Step 2: Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 7.03 moles.
For Carbon =
For Hydrogen =
Step 3: Taking the mole ratio as their subscripts.
The ratio of C : H = 1 : 2
Hence, the empirical formula for the given compound is