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zalisa [80]
4 years ago
5

Which of these is an accurate statement about scientific variables? A. They can be connected to one another. B. They are the sam

e in every experiment. C. There can only be one variable in any experiment. D. There is no way to know what variables are most important.
Chemistry
2 answers:
chubhunter [2.5K]4 years ago
4 0

The awnser is A they can be connected  to one another

inna [77]4 years ago
3 0

The correct option is A.

In scientific investigation, variable refers to those parameters that are manipulated or changed in an experiment. Variables are those factors or conditions that can exist in different amounts in a scientific investigation. There are three major types of experimental variables, these are, independent, dependent and controlled variables. All the variables that are used in an experiment are usually connected to one another, scientific investigators typically look for the relationships among the variables in order to depict how they associate with one another.

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Write a chemical equation for the dissolution of the AgCl precipitate upon the addition of NH,(aq).
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Explanation:

White precipitate of silver chloride get dissolves in excess ammonia to formation of complex between silver ions, chloride ions and ammonia molecules.

The chemical reaction is given as:

AgCl(s)+2NH_3(aq)\rightarrow Ag[(NH_3)_2]^+Cl^-(aq)

When 1 mole of silver chloride is added to 2 mole of an aqueous ammonia it form coordination complex of diaaminesilver(I) chloride.

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the first one which is A

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Determine the mass of CuSO4 • 5H20 that must be used to prepare 250mL of 2.01 M CuSO4(aq).
mario62 [17]

Given parameters:

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Concentration of CuSO₄ = 2.01M

Unknown:

Mass of CuSO₄.5H₂O = ?

To solve this problem, we must write the chemical relationship between both species.;

             CuSO₄.5H₂O  →   CuSO₄ + 5H₂O

Now that we know the expression, it is possible to solve for the unknown mass.

First find the number of moles of CuSO₄;

         Number of moles  = Concentration x Volume

Take 250mL to L so as to ensure uniformity of units;

           Volume  = 250 x 10⁻³L

  Input the parameters and solve for number of moles;

        Number of moles  = 250 x 10⁻³  x  2.01 = 0.5mol

From the equation;

             1 mole of CuSO₄ is produced from 1 mole of CuSO₄.5H₂O  

So  0.5 moles of CuSO₄ will be produced from 0.5 moles of CuSO₄.5H₂O

Now let us find the molar mass of CuSO₄.5H₂O = 63.6 + 32 + 4(16) + 5(2x1 + 16)  = 249.6g/mole

Mass of CuSO₄.5H₂O = number of moles x molar mass

                                      = 0.5 x 249.6

                                     = 124.8g

The mass of CuSO₄.5H₂O is 124.8g

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