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kykrilka [37]
3 years ago
13

THIS IS ON MY UNIT 3 STUDY GUIDE!!!!!!!!! What is a covalent compound? Write an example.

Chemistry
1 answer:
Rudiy273 years ago
3 0

water is a covalent compound which is formed by the covalent bonding between hydrogen and oxygen atoms.

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Sodium metal reacts with chlorine gas to produce sodium chloride. What mass (grams) of sodium metal would be needed to fully rea
gulaghasi [49]

Answer:

105.8 g of Na would be required

Explanation:

Let's think the reaction:

2Na(s)  + Cl₂(g)  →  2NaCl (s)

1 mol of chlorine reacts with 2 moles of sodium

Then, 2.3 moles of Cl₂ would react with (2.3 .2) / 1 = 4.6 moles

Let's determine the mass of them.

4.6 mol . 23 g/mol = 105.8 g

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Since the question is incomplete, the table has been searched in order to comply with the question.

Based on the table that I have provided, the order of increasing depth from shallowest to deepest are the following; A,B,C,D,E. The reason that this is the order to be chosen because the one responsible for making water dense is the salt that is on the water and by that, the base is likely to sink whereas the ones with less salt won’t be as thick compared those who have much salt and will skim on its top.

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Every morning, Jeremiah uses a blender to make a smoothie for breakfast. Which of the
Studentka2010 [4]

Answer:

D

Explanation:

4 0
3 years ago
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Select the correct answer.
GREYUIT [131]

Answer:HNO3 + NaOH → H2O + NaNO3

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3 years ago
What is the molarity of a solution in which 7.1 g of sodium sulfate is dissolved in enough water to make 100. mL of solution?
Sidana [21]

Answer:

0.50 M

Explanation:

Given data

  • Mass of sodium sulfate (solute): 7.1 g
  • Volume of solution: 100 mL

Step 1: Calculate the moles of the solute

The molar mass of sodium sulfate is 142.04 g/mol. The moles corresponding to 7.1 grams of sodium sulfate are:

7.1g \times \frac{1mol}{142.02g} = 0.050mol

Step 2: Convert the volume of solution to liters

We will use the relation 1 L = 1000 mL.

100mL \times \frac{1L}{1000mL} =0.100L

Step 3: Calculate the molarity of the solution

M = \frac{moles\ of\ solute }{liters\ of\ solution} = \frac{0.050mol}{0.100L} =0.50 M

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3 years ago
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